Answer:
No.
Step-by-step explanation:
y/x has to be the same number no matter what except at point (0 0) which it must also include for it to be a direct variation.
*y=2x+3 is not a direct variation because you can not write it as y/x=k where k is some constant number. If we were y=2x, then yes since y/x=2.
*You could also take two points and see if they are proportional. That is, you can see if y2/x2 gives the same value as y1/x1 where (x1,y1) and (x2,y2) are points on the line y=2x+3. This must work for every pair of points on the linear relation except at x=0 (where you would or should have y=0 if it is directly proportional).
Let's try it out. If x=1, then y=2(1)+3=5.
5/1=5
If x=2, then y=2(2)+3=7
7/2=3.5
As you can see 5 doesn't equal 3.5.
*For it to be a direct variation, it also must contain the point (0,0) and be a diagonal line when graphed. It can also be written in form y=kx where k is a constant number. This fails two of the the things I mentioned. It doesn't contain point (0,0) because y=2(0)+3=3 not 0. It cannot be written in form y=kx because of the plus 3.
If it were y=2x, then the answer would be yes.
Answer:
50.465 km
Step-by-step explanation:
In order to find the distance in kilometers, you need to first convert the marathon distance into yards. Since the conversion measurement of 1 mile = 1760 yards is given, you can use this to find the total yards in 26 miles:
or x = 45,760 yards
Adding this amount to the additional 385 in the marathon distance:
45760 + 385 = 46,145 yards
Since 1 yard = 0.9144 meters, we can find the number of meters the same way we found yards:
or m=50,465 meters
Since the question is asking for kilometers, we can need to divide the number of meters by 1000, or move the decimal point three places to the left:
50,465 ÷ 1000 = 50.465 km
AE and EC are congruent because it's given that E is the midpoint of AC. However, DE and EB cannot be congruent because it does not state that point E is the midpoint of DB.
You cannot assume that all the triangles DEA, AEB, BEC, and CED are all congruent just from being given that E is the midpoint of AC. You would need to be given other information such as "Quadrilateral ABCD is a parallelogram. "
I this helps you out with your problems
Have a nice day