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kobusy [5.1K]
2 years ago
15

Which set of data does not contain any outliners

Mathematics
1 answer:
Valentin [98]2 years ago
4 0

Answer: the answer is A i took the testssssssssssssssssssssssssss

(<*_*>)

Step-by-step explanation:

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Help please asp what does this equal:<br> 1/5.1/5.1/5
motikmotik

Answer:

0.00768935024

((1/5.1)/5.1)/5 = 0

(0.19607843/5.1)/5 = 0

0.03844675/5 = 0

0.00768935 = 0

5 0
2 years ago
Using chain rule, what is the derivative of sin(arcsin(x))
sergey [27]
Chain rule
y=f(g(x))
y´=(d f(gx)/d g)(d g/d x)

or

y=y(v)   and v=v(x), then dy /dx=(dy/dv)(dv/dx)

in our case:
y=sin (v)
v=arcsin(x)

dy/dv=d sin (v)/dv=cos (v)=cos(arcsin(x)
dv/dx=d arcsin(x)/dx=1/√(1-x²)

dy/dx=[cos (arcsin(x))]/√(1-x²)

Answer: d sin(arcsin(x))/dx=[cos (arcsin(x))]/√(1-x²)
7 0
2 years ago
Helppppppppppppppp pleaseeeeee!
stepan [7]

Answer and Explanation:

You got the first one right!

2. You do the same as you did for the first one: to combine the exponents, you multiple 2 by 9 = 18, and now 18 is your new exponent.

3^{2*9} = 3^{18} , which is the answer

3. Here, you can split up the inside so that you have:

2^5*(y^2)^5= 32*y^{2*5}=32y^{10} , which is the answer

Hope this helps! Please give me brainliest if possible.

3 0
3 years ago
Read 2 more answers
solve this problem as a quadratic equation. The difference between two positive numbers is 5. Their product is 104 find the numb
Karolina [17]
Let's call the smaller number x:

y-x=5
xy=104

y-x=5 can be rewritten as y=x+5

Substituting this into the second equation gives:

x(x+5)=104
x^2+5x=104
x^2+5x-104=0

Then simply solve as a quadratic:

x^2+13x-8x-104=0
x(x+13) -8(x+13)=0
(x-8)(x+13) = 0

x=8,-13

the question said the numbers are positive, so x=8

if x=8,

y=x+5
y=13

So the two numbers are 8 and 13.
8 0
3 years ago
Read 2 more answers
Problem 2 Find all the divisors of the number 2,310. How do you know that you found them all?​
elena-s [515]

9514 1404 393

Answer:

  1, 2, 3, 5, 6, 7, 10, 11, 14, 15, 21, 22, 30, 33, 35, 42,

  55, 66, 70, 77, 105, 110, 154, 165, 210, 231, 330, 385, 462, 770, 1155, 2310

Step-by-step explanation:

The trailing digit is 0, and the sum of digits is 6, so we know the number is divisible by 2, 3, 5. Dividing out those factors, we get a quotient of 77, which is 7×11. This means the prime factorization is ...

  2×3×5×7×11 = 2310

There are 5 prime factors, each with an exponent of 1, so the total number of divisors is 2^5 = 32. We will have found them all when all 32 are listed.

  1, 2, 3, 5, 6, 7, 10, 11, 14, 15, 21, 22, 30, 33, 35, 42,

  55, 66, 70, 77, 105, 110, 154, 165, 210, 231, 330, 385, 462, 770, 1155, 2310

Of course, the pairwise products working toward the center from the ends of the list are all 2310.

8 0
2 years ago
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