The equation described above can also be written as,
y = -x² + 100x + 4000
To get the number of notebooks that will give them the maximum profit, we derive the equation and equate to zero.
dy/dx = -2x + 100 = 0
The value of x from the equation is 50. Then, we substitute 50 to the original equation to get the profit.
y = -(50^2) + 100(50) + 4000 = 6500
Thus, the maximum profit that the company makes is $6,500/day.
Answer:
$75.65
Step-by-step explanation:
First, converting R percent to r a decimal
r = R/100 = 4.25%/100 = 0.0425 per year,
then, solving our equation
I = 890 × 0.0425 × 2 = 75.65
I = $ 75.65
The simple interest accumulated
on a principal of $ 890.00
at a rate of 4.25% per year
for 2 years is $ 75.65.
Answer:
6cm
Step-by-step explanation:
Given data
Width= 4.6cm
Length= 9cm
Volume= 82.8cm^3
The expression for the volume is given as
V= lwh/3
82.8= 9*4.6*h/3
cross multiply
82.8*3= 9*4.6*h
248.4= 41.4h
h= 248.4/41.4
h= 6cm
Answer:
525 x 1,050
A = 551,250 m²
Step-by-step explanation:
Let 'L' be the length parallel to the river and 'S' be the length of each of the other two sides.
The length of the three sides is given by:

The area of the rectangular plot is given by:

The value of 'S' for which the area's derivate is zero, yields the maximum total area:

Solving for 'L':

The largest area enclosed is given by dimension of 525 m x 1,050 and is:

Answer:
110 grams
Step-by-step explanation:
CO2 molecule is made up of Carbon (atomic mass =12) and oxygen (atomic mass=16).
So first finding the mass of 1 molecule of CO2 which is equals to
= mass of 1 carbon atom + masses of 2 oxygen atom, we get
= 12+(16*2)= 12+32= 44 a.m.u.
Now 1 molecule of CO2 has mass 44 amu so mass of 1 mole CO2 will be 44 grams.( 1 a.m.u.=1.6729*10^-33 grams. 1 mole = 6.022*10^23, so 44 a.m.u.=73.6076*10^-33 grams approx. For one mole CO2, 73.6076*10^-33*6.022*10^23 which is approximately equals to 44 grams. )
1 mole CO2= 44grams, so 2.5 moles = 44*2.5= 110 grams
So our answer is 110 grams.
lowkey hope this helped you, good luck whatever you need it for Imaooo