Answer:(x^2+y^2)^2=(x^2+y^2)(x^2+y^2)
Step-by-step explanation:
We can rewrite left side into right side form
(x^2+y^2)^2=(x^2+y^2)(x^2+y^2)
we can expand it
(x^2+y^2)^2=x^4+x^2y^2+x^2y^2+y^4
(x^2+y^2)^2=x^4+y^4+2x^2y^2
we can add and subtract 2x^2y^2
(x^2+y^2)^2=x^4+y^4+2x^2y^2+2x^2y^2-2x^2y^2
(x^2+y^2)^2=x^4-2x^2y^2+y^4+2x^2y^2+2x^2y^2
(x^2+y^2)^2=x^4-2x^2y^2+y^4+4x^2y^2
(x^2+y^2)^2=x^4-2x^2y^2+y^4+(2xy)^2
(x^2+y^2)^2=(x^2-y^2)^2+(2xy)^2
Y=1/2x i think , cuz the rate of change is 1/2
Answer:
c
Step-by-step explanation:
Answer:
its B. A = 0t3 B = (–0.6t2) C = 18t D = (–8)
the next answer is D. 1.3^3 - 0.2t^2 - 6t - 8
Answer:
Step-by-step explanation:
First, move the -11/4 to the other side, so the expression can equal 0.

To make the equation easier to work with, multiply both sides by 4, cancelling out the fraction.

There are many ways to solve a quadratic equation (factoring, quadratic formula, completing the square).
Solving this equation by factoring is the easiest. Factoring with a leading coefficient greater than one can be difficult and there are many ways to accomplish it. The way I'm going to do it is to first find the factors of
and then the factors of 11. And then multiply across, add the middle terms (derived from multiplying) and try to make it equal 24x.
: 24x 11:
2x 22x 11
2x 2x 1
24x (works)
I'll then take the factors diagonal. (2x+1)(2x+11)=0
So 