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Valentin [98]
3 years ago
6

A roast beef sandwich cost $6.75. A customer buys multiple sandwiches. Write and equation using x to represent the number of san

dwiches
Mathematics
2 answers:
GREYUIT [131]3 years ago
4 0

Answer:

y = 6.75x

Step-by-step explanation:

Shalnov [3]3 years ago
4 0

Answer:

Step-by-step explanation:

She gives 4 pumpkins

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Perpendicular lines form 90 degree angles. It creates 4 of them, to be exact. Hope this helps! :)

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Which of the following is an arithmetic sequence?–20, –25, –30, –35, –45, ...
timurjin [86]
B) -15.6,-12.9,-10.2,-7.5,-4.8

This is an arithmetic sequence. 
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3 years ago
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If 150g of sugar is used for 5 cakes<br> How much is used for 7 cakes?:)
KIM [24]
Well, if 150 grams is used for 5 cakes, we can divide that.
150/5=30. 30 grams of sugar are used for each cake
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3 years ago
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Match the expression with its name.
IrinaVladis [17]
Ax^2 + bx + c is a quadratic trinomial. Therefore, ur expression is a quadratic trinomial......it is a trinomial because it has 3 terms.....quadratic means the highest exponent is 2.
6 0
3 years ago
Can someone help me find the equivalent expressions to the picture below? I’m having trouble
miss Akunina [59]

Answer:

Options (1), (2), (3) and (7)

Step-by-step explanation:

Given expression is \frac{\sqrt[3]{8^{\frac{1}{3}}\times 3} }{3\times2^{\frac{1}{9}}}.

Now we will solve this expression with the help of law of exponents.

\frac{\sqrt[3]{8^{\frac{1}{3}}\times 3} }{3\times2^{\frac{1}{9}}}=\frac{\sqrt[3]{(2^3)^{\frac{1}{3}}\times 3} }{3\times2^{\frac{1}{9}}}

           =\frac{\sqrt[3]{2\times 3} }{3\times2^{\frac{1}{9}}}

           =\frac{2^{\frac{1}{3}}\times 3^{\frac{1}{3}}}{3\times 2^{\frac{1}{9}}}

           =2^{\frac{1}{3}}\times 3^{\frac{1}{3}}\times 2^{-\frac{1}{9}}\times 3^{-1}

           =2^{\frac{1}{3}-\frac{1}{9}}\times 3^{\frac{1}{3}-1}

           =2^{\frac{3-1}{9}}\times 3^{\frac{1-3}{3}}

           =2^{\frac{2}{9}}\times 3^{-\frac{2}{3} } [Option 2]

2^{\frac{2}{9}}\times 3^{-\frac{2}{3} }=(\sqrt[9]{2})^2\times (\sqrt[3]{\frac{1}{3} } )^2 [Option 1]

2^{\frac{2}{9}}\times 3^{-\frac{2}{3} }=(\sqrt[9]{2})^2\times (\sqrt[3]{\frac{1}{3} } )^2

                =(2^2)^{\frac{1}{9}}\times (3^2)^{-\frac{1}{3} }

                =\sqrt[9]{4}\times \sqrt[3]{\frac{1}{9} } [Option 3]

2^{\frac{2}{9}}\times 3^{-\frac{2}{3} }=(2^2)^{\frac{1}{9}}\times (3^{-2})^{\frac{1}{3} }

               =\sqrt[9]{2^2}\times \sqrt[3]{3^{-2}} [Option 7]

Therefore, Options (1), (2), (3) and (7) are the correct options.

6 0
3 years ago
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