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natulia [17]
3 years ago
12

I’m the figure below angle y and angle x form vertical angles angle x forms a straight line with the 50 degree angle and the 40

degree angle write and solve an equation to determine the angle of y
Mathematics
1 answer:
kenny6666 [7]3 years ago
5 0
I don’t really even know
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Y= 1/2x -2 is the equation for this line.
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What is the slope of the line containing the points (1,-1) and (3,3)
marishachu [46]

Answer:

1

Step-by-step explanation:

1111111111111111111

4 0
3 years ago
This composite figure is made up of three simpler shapes. What is the area of the figure? 7 cm 4 cm 5 cm 4 CE 8 cm A. 66 square
kirza4 [7]

The total area of the given figure will be 66 square cm.

<h3>What is an area? </h3>

The space occupied by any two-dimensional figure in a plane is called the area. Here we have three shapes a triangle, a rectangle and a parallelogram.

Total area = Area of triangle + Area of rectangle + Area of parallelogram

Total area = [(1/2) x 4 x7]   +  [4  x  5]  + [ 4   x   8 ]

Total area =  14+20+32

Total area = 66 square cm

Hence the total area of the given figure will be 66 square cm.

To know more about the area follow

brainly.com/question/24375372

#SPJ1

5 0
2 years ago
a student walks 50m on a bearing 0.25 degrees and then 200m due east how far is she from her starting point.​
Inessa05 [86]

Answer:

Step-by-step explanation:

I'm going to use Physics here for this concept of vectors. Here are some stipulations I have set for the problem (aka rules I set and then followed throughout the problem):

** I am counting the 50 m as 2 significant digits even though it is only 1, and I am counting 200 as 3 significant digits even though it is only 1. 1 sig dig doesn't really give us enough accuracy, in my opinion.

** A bearing of .25 degrees is measured from the North and goes clockwise; that means that measured from the x axis, the angle is 89.75 degrees. This is the angle that is used in place of the bearing of .25 degrees.

** Due east has an angle measure of 0 degrees

Now let's begin.

We need to find the x and y components of both of these vectors. I am going to call the first vector A and the second B, while the resultant vector will be C. Starting with the x components of A and B:

A_x=50cos(89.75) so

A_x=.22

B_x=200cos(0) so

B_x=200 and we need to add those results together. Due to the rules for adding significant digits properly, the answer is

C_x=200 (and remember I am counting that as 3 sig fig's even though it's only 1).

Now for the y components:

A_y=50sin(89.75) so

A_y=50 (which I'm counting as 2 sig fig's)

B_y=200sin(0) so

B_y=0 and we need to add those results together.

C_y=50

Now for the resultant magnitude:

C_{mag}=\sqrt{(200)^2+(50)^2}  and that gives us a final magnitude of

C_{mag}=206 m

Now for the angle:

Since both the x and y components of the resultant vector are in quadrant 1, we don't need to add anything to the angle to get it right, so

tan^{-1}(\frac{50}{200})=14

The girl is 206 meters from her starting point at an angle of 14 degrees

4 0
3 years ago
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