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sammy [17]
3 years ago
7

How do i solve this inequality? Number 46

Mathematics
1 answer:
myrzilka [38]3 years ago
7 0
6(x-2.5) ≥ 8-6(3.5+x)

A number is before a parenthesis. The first step is to multiply.

6(x-2.5) = 6x -15

8-6(3.5+x)
2(3.5+x)= 7+2x

6x-15≥7+2x

Now solve

6x-15≥7+2x
-2x -2x

(-2x+2x)= They cancel out

(6x-2x)= 4x

4x-15≥7
+15 +15

4x≥22
/4 /4

You get= x≥5.5
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Difference of the squares of the numbers=x^2-y^2=5

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Putting the values in the identity

(x^2+y^2)^2=(5)^2+[2(6)]^2\\=25+(12)^2\\=25+144\\=169

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Learn more about identities at:

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