Write down all the odd numbers and add from there. I hope this helped!
Certain because the papers are labeled from 1 - 12, thus you will always pick out a number less than 15.
Answer:
Step-by-step explanation:
To solve this problem, first you have to isolate it on one side of the equation. To solve this problem, division property of equality is divide both sides of an equation by the same number doesn't change the equation.
First, divide by 6 from both sides.
6(n-6)/6<-108/6
Solve.
-108/6=-18
6n-6<-18
Next, add 6 from both sides.
6n-6+6<-18+6
Solve.
-18+6=-12
6n<-12
Then, divide by 6 from both sides.
6n/6<-12/6
Solve.
-12/6=-2
As a result, the correct answer is n<-2.
<h2>Hope this helps!</h2><h2 /><h2>Have a wonderful blessing day! :)</h2><h2 /><h2>Good luck! :)</h2>
R=-7, you have to put each answer in the equation, therefore; 21=42-3(-7) So you have to do multiplication (PEMDAS, if you arent aware of that acronym then it stands for the order of what to do with an equation, Parentheses get solved first, then Exponents, then multiplication, then division, then addition, then finally subtraction. Solving in that order will solve your answer correctly.) With -3 times -7 which gives you 21. Then you do 42 - 21 which equals 21. So 21 = 21.
Answer:
45 members are in the choir.
Step-by-step explanation:
Set up an equation:
Variable x = boys
3/6 = x/30
Cross multiply:
3 × 30 = 6 × x
90 = 6x
Divide both sides by 6:
15 = x
There are 15 boys.
To find the number of members in the choir, add the number of boys and girls:
30 + 15 = 45
