Answer:
We accept H₀ for a CI = 95 % we din´t find differences in the unemployment level
Step-by-step explanation:
p₀ = 12 % p₀ = 0,12
From sample p = 53/500 p = 0,106
Test Hypothesis
Null Hypothesis H₀ p = p₀
Alternative Hypothesis Hₐ p < p₀
p₀*n = 0,12*500 = 60
q₀ * n = 0,88 * 500 = 440
Then the binomial distribution can be approximate to a normal distribution
The significance level α = 0,05 CI = 95 %
We need to develop a one-tail test (to the left ) find p-value and compare it with α.
p(s) = ( p - p₀ ) / √ p*q /n
p(s) = 0,106 - 0,12 / √(0,12)*(0,88)/500
p(s) = - 0,014 / 0,015
p(s) = - 0,93
With this P score we find the area under the bell shape curve
p-value = 0,1762 and compare that area with α = 0,05
Then p-value > 0,05
Therefore we accept H₀
