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3 years ago

5

The following data indicate the scores of some students in a competition:

2 answers:

Delicious77 [7]3 years ago

7 0

Answer: The correct choice is the third choice.

First, lets look at the whiskers. They go out to the minimum and maximum. Our whiskers will need to go out to 11 and 32.

Second, lets look at the box. The range of the box is from 14 to 31 because those are the lower and upper quartile.

Finally, the middle line of the box is the median. In our case the median is 23.

These three facts lead us to chose the third option.

Elenna [48]3 years ago

6 0

Answer:The answer is c

Step-by-step explanation:

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3 years ago

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maks197457 [2]

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3 years ago

Convert the Cartesian equation (x 2 + y 2)2 = 4(x 2 - y 2) to a polar equation.

SashulF [63]

<u>ANSWER</u>

${r}^{2} = 4 \cos2\theta$

<u>EXPLANATION</u>

The Cartesian equation is

${( {x}^{2} + {y}^{2} )}^{2} = 4( {x}^{2} - {y}^{2} )$

We substitute

$x = r \cos( \theta)$

$y = r \sin( \theta)$

and

${x}^{2} + {y}^{2} = {r}^{2}$

This implies that

${( {r}^{2} )}^{2} = 4(( { r \cos\theta) }^{2} - {(r \sin\theta) }^{2} )$

Let us evaluate the exponents to get:

${r}^{4} = 4({ {r}^{2} \cos^{2}\theta } - {r}^{2} \sin^{2}\theta)$

Factor the RHS to get:

${r}^{4} = 4{r}^{2} ({ \cos^{2}\theta } - \sin^{2}\theta)$

Divide through by r²

${r}^{2} = 4 ({ \cos^{2}\theta } - \sin^{2}\theta)$

Apply the double angle identity

$\cos^{2}\theta -\sin^{2}\theta= \cos(2 \theta)$

The polar equation then becomes:

${r}^{2} = 4 \cos2\theta$

7 0

3 years ago