The following data indicate the scores of some students in a competition:

2 answers:

7 0

Answer: The correct choice is the third choice.

First, lets look at the whiskers. They go out to the minimum and maximum. Our whiskers will need to go out to 11 and 32.

Second, lets look at the box. The range of the box is from 14 to 31 because those are the lower and upper quartile.

Finally, the middle line of the box is the median. In our case the median is 23.

These three facts lead us to chose the third option.

Elenna [48]3 years ago

6 0

Answer:The answer is c

Step-by-step explanation:

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2=ln(x+7) solve for x

maria [59]

Answer:

e^2 -7 = x

Step-by-step explanation:

2=ln(x+7)

Raise each side to the base of e

e^2 = e^ln (x+7)

The e^ln cancel

e^2 = x+7

Subtract 7 from each side

e^2 -7 = x +7-7

e^2 -7 = x

8 0

3 years ago

Students in a zoology class took a final exam. They took equivalent forms of the exam at monthly intervals thereafter. After t

juin [17]

Answer:

a. 73; b. 48.9; c. 2; d. 33.8; e. 73

Step-by-step explanation:

Assume the function was

S(t)= 73 - 15 ln(t + 1), t ≥ 0

a. Average score at t = 0

S(0) = 73 - 15 ln(0 + 1) = 73 - 15 ln(1) = 73 - 15(0) =73 - 0 = 73

b. Average score at t = 4

S(4) = 73 - 15 ln(4 + 1) = 73 - 15 ln(5) = 73 - 15(1.61) =73 - 24.14 = 48.9

c. Average score at t =24

S(24) = 73 - 15 ln(24 + 1) = 73 - 15 ln(25) = 73 - 15(3.22) =73 - 48.28 = 24.7

d. Percent of answers retained

At t = 0. the students retained 73 % of the answers.

At t = 24, they retained 24.7 % of the answers.

$\text{Percent retention} = \dfrac{\text{24.7}}{\text{73}} \times 100 \, \% = \text{33.8 \%}\\\\\text{The students retained $\large \boxed{\mathbf{33.8 \, \%}}$ of their original knowledge after two years.}$