All categories

2 years ago

Which of the following is not a measure of central tendency?

Mathematics

2 answers:

Effectus [21]2 years ago

5 0

Answer:d). standard deviation

Step-by-step explanation:

Alinara [238K]2 years ago

4 0

D. Standard deviation

You might be interested in

Susie’s Sweet Shop sells chocolate boxes that contain three types of chocolate truffles: solid chocolate truffles, cream center

olganol [36]

Let us make a list of all the details we have

We are given

The cost of each solid chocolate truffle = s

The cost of each cream centre chocolate truffle = c

The cos to each chocolate truffle with nuts = n

The first type of sweet box that contains 5 each of the three types of chocolate truffle costs $41.25

That is 5s+5c+5n = 41.25 (cost of each type of truffle multiplied by their respective costs and all added together)

The second type of sweet box that contains 10 solid chocolate trufles, 5 cream centre truffles and 10 chocolate truffles with nuts cost $68.75

That is 10s+5c+10n = $68.75

The third type of sweet box that contains 24 truffles evenly divided that is 12 each of solid chocolate truffle and chocolate truffle with nuts cost $66.00

That is 12s+12n=$66.00

Hence option C is the right set of equations that will help us solve the values of each chocolate truffle.

6 0

3 years ago

The ages of the Oscar-winners for best actor and actress for the years 1970 through 1990 are given below: Women: 34, 34,26,37,42

Artemon [7]

Answer:

See explanation below.

Step-by-step explanation:

Numerical way

We can calculate the mean and the standard deviation from a sample with the following formulas:

$\bar X = \frac{\sum_{i=1}^n X_i}{n}$

$s= \frac{\sum_{i=1}^n (X_i -\bar X)^2}{n-1}$

We have the following dataset for women: 34,34,26,37,42,41,35,31,41,33,30,74,33,49,38,61,21,41,26,80,72

And the mean and deviation are:

$\bar X_F = 41.857$

$s_F = 16.399$

We can calculate the median ordering the data like this:

21,26,26,30,31,33,33,34,34,35,37,38,41,41,41,42,49,61,72,74,80

And the median would be on the 11 position of the data ordered, for this case is:

$median_F = 37$

$Minimum_F = 21 , Maximum_F = 80$

And the range is given by: $Range_F = 80-21=59$

We can also calculate the coefficient of variation given by:

$\hat{CV} =\frac{s}{\bar X} = \frac{16.399}{41.857}=0.392$

We have the following dataset for men:

43, 40,48,48,56,38,60,32,40,42,37,76,39,55,45,35,61,33,51,32,42

And the mean and deviation are:

$\bar X_M = 45.381$

$s_M = 11.218$

We can calculate the median ordering the data like this:

32, 32,33,35,37,38,39,40,40,42,42,43,45,48,48,51,55,56,60,61,76

And the median would be on the 11 position of the data ordered, for this case is:

$median_M = 42$

$Minimum_M = 32 , Maximum_F = 76$

And the range is given by: $Range_M = 76-32=44$

We can also calculate the coefficient of variation given by:

$\hat{CV} =\frac{s}{\bar X} = \frac{11.218}{45.381}=0.247$

We se that the mean for the male groups is higher than the mean for female group. The deviation is higher for the female group comapred to the male group. We have more variation for the female group as we can see on the range and the coeffcient of variation.

Graph

We can see the histograms for each group on the figures attached.

As we can see the histogram for males is skewed to the right with the median lower than the mean.

By the other hand the histogram for the female group seems to be skewed to the right also but with missing values on the interval 50-60, for this reason we have more variation compared to the male group.