Answer:
(silk butterfly numerator )(butterfly denominator) 4cm/20cm = 1cm/5cm
Answer:

Step-by-step explanation:
In the Slope-Intercept Formula,
, <em>b</em><em> </em>represents the y-intercept, and the <em>rate of</em><em> </em><em>change</em><em> </em>[<em>slope</em>] is represented by <em>m</em>,<em> </em>so the slope is −⅔.
I am joyous to assist you anytime.
Answer:
He needs 3.75 lbs of sugar and 1.25 lbs of water.
Step-by-step explanation:
Let x lbs be the amount of sugar in the syrup. Then 5-x lbs is the amount of water in this syrup.
Note
5 lbs - 100%
x lbs - 75%
Write a proportion:

Cross multiply:

So, he needs 3.75 lbs of sugar and 5 - 3.75 = 1.25 lbs of water.
Answer:
1. a. Weak
2. r^2=0.0169
The variation in the price of the wine explained by the variation in the weight of the bottle is 1.69%.
Step-by-step explanation:
The correlation between the weight of the wine bottles and the price of the wine is r=0.13.
The values for r goes from r=-1, where a perfect negative correlation to r=1 for a perfect positive correlation. The value r=0 indicates no correlation at all.
Then, a value of r close to 0 indicates very weak correlation between the two variables.
The value for r^2 in this case is:

The value of r2 can be interpreted as the proportion of the variation in the dependant variable explained by the independent vairable. In this case, the variation in the price of the wine explained by the variation in the weight of the bottle is 1.69%, which is very close to 0.