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Answer:
<em>63.44 rad/s</em>
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Explanation:
mass of bullet = 3.3 g = 0.0033 kg
initial velocity of bullet = 250 m/s
final velocity of bullet = 140 m/s
loss of kinetic energy of the bullet =
==> = 70.785 J
this energy is given to the stick
The stick has mass = 250 g =0.25 kg
its kinetic energy = 70.785 J
from
KE =
70.785 =
566.28 =
= 23.79 m/s
the stick is 1.5 m long
this energy is impacted midway between the pivot and one end of the stick, which leaves it with a radius of 1.5/4 = 0.375 m
The angular speed will be
Ω = v/r = 23.79/0.375 =<em> 63.44 rad/s</em>