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babymother [125]
3 years ago
11

I need an answer asap

Physics
1 answer:
gulaghasi [49]3 years ago
5 0
He has a mass of 56 kg.

The equation given is PE = mgh.

PE = 4620 J

h = 8.4

g = 9.8

Therefore:

4620 = 82.32m

m = 4620/82.32
m = 56 (rounded to two significant digits)
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A 6.0 kg mass is placed on a 20º incline which has a coefficient of friction of 0.15. What is the acceleration of the mass down
Leona [35]

Answer:

Explanation:

The form of Newton's 2nd Law that we use for this is:

F - f = ma where F is the Force pulling the mass down the ramp forward, f is the friction trying to keep it from moving forward, m is the mass and a is the acceleration (and our unknown).

We know mass and we can find f, but we don't have F. But we can solve for that by rewriting our main equation to reflect F:

wsin\theta-\mu F_n=ma That's everything we need.

w is weight: 6.0(9.8). Filling in:

6.0(9.8)sin20 - .15(6.0)(9.8) = 6.0a and

2.0 × 10¹ - 8.8 = 6.0a and

11 = 6.0a so

a = 1.8 m/s/s

6 0
3 years ago
Random errors can be reduced by taking repeated measurements.Error and uncertainty are interchangeable words that describe the s
fiasKO [112]

repeated mesurement can reduce the error

it is true

if you take any mesurement repeatedly and the average is taken, the error will be less

5 0
1 year ago
Will upvote
Debora [2.8K]
Bike
because it involves lots of angular mechanics that allow it to balance itself when moving.

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3 0
3 years ago
What does the change of motion of an object depend on?
IrinaVladis [17]

Answer:

I think the answer is B

Explanation:

4 0
3 years ago
Read 2 more answers
A tiger paces back and forth along the front of its cage, which is 8 m wide. The tiger starts from the right side of the cage, p
Black_prince [1.1K]

Answer:

The total distance is 24 m.

The tiger's resultant displacement is 8 m.

Explanation:

Given that,

Width of tiger= 8 m

Tiger starts from the right side of the cage,

Paces to the left side

\Delta x_{1}=+8\ m

Then, back to the right side,

\Delta x_{2}=-8\ m

finally, back to the left

\Delta x_{3}=+8\ m

We need to calculate the total distance covered

Using formula of distance

d= x_{1}+x_{2}+x_{3}

Put the value into the formula

d=8+8+8

d=24\ m

We need to calculate the tiger's resultant displacement

Using formula of displacement

D=\Delta x_{1}+\Delta x_{2}+\Delta x_{3}

Put the value into the formula

D=8+(-8)+8

D=8\ m

Hence, The total distance is 24 m.

The tiger's resultant displacement is 8 m.

3 0
3 years ago
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