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just olya [345]
3 years ago
15

How much heat is required to warm 122 g of water by 23.0 c?

Physics
2 answers:
Pachacha [2.7K]3 years ago
6 0

Answer: 11745.92 j

Explanation: using heat = mc∆

Where k is mass

C is heat capacity of water = 4.186 j/gc

∆ is temperature

H = 122 × 4.186 × 23

= 11745.92 j

GaryK [48]3 years ago
4 0
<span>122 g * 4,186 (j/g*°c) * 23°c = 11745.916 j </span>
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Answer:

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we have:

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