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PolarNik [594]
3 years ago
6

The right ventricle transports oxygenated blood to the lungs.

Physics
2 answers:
juin [17]3 years ago
5 0

Answer: False

Explanation: The circulatory system of the body consists of the heart, blood vessels and blood. The deoxygenated blood from the body is carried to the heart.

Here, the deoxygentaed blood is converted into oxygenated by removing carbon dioxide from them and making it oxygenated.

The impure blood from the body is collected by the right ventricle and transported to the lungs for purification and then transported to the body.

gtnhenbr [62]3 years ago
4 0

The correct answer is F (False)

Explanation:

In anatomy, the heart which is the organ in charge of pumping blood to all the body is divided into different sections that include the aorta, the superior vena cava, the right/left atrium, the pulmonary valve, and the right/left ventricles. In the case of the right ventricle, this is a chamber located on the right side of the hearth and the main function of this is to pump blood that is low in oxygen or de-oxygenated blood to the lungs through the pulmonary artery. On the other hand, the left ventricle pumps oxygenated blood to all the body. This implies, it is false the right ventricle transports oxygenated blood to the lungs because it pumps de-oxygenated rather than oxygenated blood.

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b

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What happens to a current when the electric field in the wire increase
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Two parallel wires carry currents in the same direction. If the currents in the wires are 1A and 4A and the wires are 5 m apart.
serious [3.7K]

Answer:

1.6\times 10^{-7} N

2.4\times 10^{-7} N

Explanation:

i_{1} = 1 A

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F = Force per unit length acting between the two wires

Force per unit length acting between the two wires is given as

F = \frac{\mu _{o}}{4\pi }\frac{2i_{1}i_{2}}{r}

F = (10^{-7})\frac{2(1)(4)}{5}

F = 1.6\times 10^{-7} N

r'} = distance of each wire from the midpoint = 2.5 m

Magnetic field midway between the two wires is given as

B = \frac{\mu _{o}}{4\pi } \left \left ( \frac{2i_{2}}{r'} \right - \frac{2i_{1}}{r'} \right \right ))

B = (10^{-7}) \left \left ( \frac{2(4)}{2.5} \right - \frac{2(1)}{2.5} \right \right ))

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5 0
3 years ago
A 9.0-V battery (with nonzero resistance) and switch are connected in series across the primary coil of a transformer. The secon
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Answer:

N₂ / N₁ = 13.3

Explanation:

A transformer is a system that induces a voltage in the secondary due to the variation of voltage in the primary, the ratio of voltages is determined by the expression

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where ΔV₂ and ΔV₁ are the voltage in the secondary and primary respectively and N is the number of windings on each side.

In this case, they indicate that the primary voltage is 9.0 V and the secondary voltage is 120 V

therefore we calculate the winding ratio

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         N₂ / N₁ = 120/9

         N₂ / N₁ = 13.3

s good clarify that in transformers the voltage must be alternating (AC)

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