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2 years ago

An acrobat on skis starts from rest 50.0 m above the

Physics

1 answer:

Brums [2.3K]2 years ago

4 0

The initial speed of the skier is 14 m/s.

The maximum height attained by the skier is 15 m.

<h3>Initial speed of the skier</h3>

The initial speed of the skier is determined by using the following kinematic equation.

$K.E = mgh\\\\\frac{1}{2} mv^2 = mgh\\\\\frac{1}{2} v^2 = gh\\\\v^2 = 2gh\\\\v = \sqrt{2gh} \\\\v = \sqrt{2\times 9.8 \times 10} \\\\v = 14 \ m/s$

<h3>Maximum height attained</h3>

The maximum height attained by the skier is calculated as follows;

$H = \frac{v^2 sin^2\theta}{2g} \\\\H = \frac{14^2 \times (sin45)^2}{2 \times 9.8} \\\\H = 5 \ m$

Thus, the maximum height attained by the skier is (10 + 5) = 15 m.

Learn more about maximum height of projectile here: brainly.com/question/12870645

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Mekhanik [1.2K]

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as it it is made up of more than 1 type of ion.

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4 0

2 years ago

A 20 kg wagon is rolling to the right across a floor. A person attempts to catch and stop the crate and applies a force of 70 N,

Serggg [28]

Answer:

1.736m/s²

Explanation:

According to Newton's second law;

$\sum F_x = ma_x\\$

$Fm - Ff = ma_x\\$ where;

Fm is the moving force = 70.0N

Ff is the frictional force acting on the body

$Ff = \mu R\\Ff = \mu mg\\$

$\mu$ is the coefficient of friction

m is the mass of the object

g is the acceleration due to gravity

a is the acceleration/deceleration

The equation becomes;

$Fm - Ff = ma_x\\Fm - \mu mg = ma\\$

Substitute the given parameters

$Fm - \mu mg = ma\\70 - 0.18(20)(9.8) = 20a\\70-35.28 = 20a\\34.72 = 20a\\a = \frac{34.72}{20}\\a = 1.736m/s^2\\$

Hence the deceleration rate of the wagon as it is caught is 1.736m/s²

7 0

3 years ago

Introduced species often thrive and multiply in an environment very different from their original one. Why are they often able t

Anestetic [448]

They begin to adapt into their new location. They then end up having adaptations to help them survive.

8 0

2 years ago

14.A 90 kg quarterback gets tackled by being hit by a 120 kg lineman backwards

quester [9]

The acceleration of the quarterback and the lineman is 5.55m/s² and 4.16m/s² respectively in the same direction.

As, we know, the 120 Kg lineman is moving with a force of 500N.

His net acceleration will be in the same direction as his motion.

It is already known that, If M is the mass of the body and a is the acceleration of the body, then the force F on the body can be calculated by using the formula,

F = Ma.

The weight of the quarterback is 90 Kg. He is being hit by a force of 500N.

So, the acceleration can be calculated using the formula,

500N = 90kg x a

a = 5.55 m/s².

Now, the weight if the lineman is 120kg, the force applied by him is 500N.

So, from the formula, his acceleration A will be,

500N = 120Kg x A

A = 4.16 m/s².

both of them will have acceleration in the same direction,

To know more about Force, visit,

brainly.com/question/25239010

#SPJ9

8 0

9 months ago

Please help me quickly!!!

vichka [17]

Hey! So referring to the data the thing we can clearly see is that in a vacuum, everything, regardless of its mass, falls at the same speed.

Acceleration is often confused with speed, or velocity, but the difference is, acceleration by definition is the rate of which an object falls with respect to its mass and time.

Every single thing in the world falls at the same acceleration, this is because of gravity. The difference is the speed of which it falls. In space, there is not any gravity, and so, the objects are able to fall at the same speed regardless of their mass.

6 0

3 years ago