Ask question

Ask question

All categories

3 years ago

15

Find two mixed numbers so that the sum is 21 1/6 and the difference is 4 3/6

1 answer:

docker41 [41]3 years ago

6 0

A + b = 21 1/6 --> b = 21 1/6 - a
a - b = 4 3/6

a - (21 1/6 -a) = 4 3/6
a - 21 1/6 + a = 4 3/6
2a = 21 1/6 + 4 3/6
2a = 25 4/6
2a = 154/6
a = (154/6) / 2
a = (154/6) * (1/2)
a = 154/12
a = 12 10/12
a = 12 5/6

b = 21 1/6 -a
b = 21 1/6 - 12 5/6
b = 20 7/6 - 12 5/6
b = 8 2/6

Answer:
a = 12 5/6
b = 8 2/6

Double check:

a + b = 12 5/6 + 8 2/6
a + b = 20 7/6 ......(7/6 = 6/6 + 1/6)
a + b = 21 1/6

a - b = 12 5/6 - 8 2/6
a - b = 4 3/6

You might be interested in

In a survey of 100 people, some of them jog for exercise, some of them ride a bike, some do both, and 15 do not jog or ride a bi

masya89 [10]

Answer:

Bike alone = 39

Step-by-step explanation:

Given that:

Total number = n(T) = 100

Jog= n(J)

Bike = n(B)

Bike and jog = n(BnJ) = 21

Number who jog = 46

Jog alone = 46 - 21 = 25

Neither jog nor bike = 15

Let bike alone = x

Hence,

Jog alone + bike alone + jog and bike + none of the two = 100

25 + x + 21 + 15 = 100

x = 39

8 0

4 years ago

PLS PLS ASAP<br> Find the value of x.

Arlecino [84]

Answer:

x = 10 units

Step-by-step explanation:

16 is to 40 as x+2 is to 3x

16/40 = (x+2) / 3x

48x = 40x + 80

8x = 80

x = 10

3 0

2 years ago

What is the GFC of 40 and 60

Svetradugi [14.3K]

Answer:

GCF: 20

Step-by-step explanation:

The thing you want to do is factor both numbers down to their lowest primes.

40:2 * 2 * 2 * 5

60:2 * 2 * 5 * 3

Now underline what is in both sets of primes. I'll bold them. The number that is bolded comes from 2 * 2 * 5 which is 20

The highest common factor is 20

3 0

3 years ago

Write the equation for the quadratic function in standard form

Ede4ka [16]

Answer:

$y=x^2+6x+7$

Step-by-step explanation:

To write the quadratic in standard form, begin by writing it in vertex form

$y = a(x-h)^2+k$

Where (h,k) is the vertex of the parabola.

Here the vertex is (-3,-2). Substitute and write:

$y=a(x--3)^2+-2\\y=a(x+3)^2-2$

To find a, substitute one point (x,y) from the parabola into the equation and solve for a. Plug in (0,7) a y-intercept of the parabola.

$7=a((0)+3)^2-2\\7=a(3)^2-2\\7=9a-2\\9=9a\\1=a$

The vertex form of the equation is $y=(x+3)^2-2$ .

To write in standard form, convert vertex form through the distributive property.

$y=(x+3)^2-2\\y=(x^2+6x+9)-2\\y=x^2+6x+7$

8 0

4 years ago

Which applies the power of a product rule simplify

liberstina [14]

<em>so</em><em> </em><em>the</em><em> </em><em>right</em><em> </em><em>answer</em><em> </em><em>is</em><em> </em><em>of</em><em> </em><em>option</em><em> </em><em>C</em><em>.</em>

<em>Look</em><em> </em><em>at</em><em> </em><em>the</em><em> </em><em>attached</em><em> </em><em>picture</em><em> </em><em>⤴</em>

<em>Hope</em><em> </em><em>it</em><em> </em><em>will</em><em> </em><em>help</em><em> </em><em>u</em><em>.</em><em>.</em><em>.</em>

5 0

3 years ago