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3 years ago

The Largest Natural Number Exactly Divides The Product of any four Natural numbers,is ?

Mathematics

1 answer:

nevsk [136]3 years ago

8 0

Answer:

The correct answer is option <u>"C".</u>

Step-by-step explanation:

let the four consecutive numbers be a ,a+1 ,a+2 & a+3.

In these four consecutive natural numbers we will have : -

= One number which is multiple of 2 but not a multiple of 4.

= One number which is multiple of 3.

= One number which is multiple of 4.

so that the product of the 4 consecutive numbers will be<u> divisible by 2x3x4 = 24. </u>

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The graphs below have the same shape. What is the equation of the blue

d1i1m1o1n [39]

Answer:

Step-by-step explanation:

4 0

3 years ago

A nike bag cost $122 if for the holiday it's marked down by 20%. What is the total cost after tax if the tax is 8%

Sindrei [870]

The answer would be 105.41
Explantaion: 122 • 0.2=24.4
122-24.4=97.6
97.6•0.08=7.808 which rounded to the nearest hundredths would be 7.81 then 97.6+7.81=105.41

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3 years ago

Find the first partial derivatives of the function f(x,y,z)=4xsin(y−z)

Amanda [17]

Answer:

$f_x(x,y,z)=4\sin (y-z)$

$f_x(x,y,z)=4x\cos (y-z)$

$f_z(x,y,z)=-4x\cos (y-z)$

Step-by-step explanation:

The given function is

$f(x,y,z)=4x\sin (y-z)$

We need to find first partial derivatives of the function.

Differentiate partially w.r.t. x and y, z are constants.

$f_x(x,y,z)=4(1)\sin (y-z)$

$f_x(x,y,z)=4\sin (y-z)$

Differentiate partially w.r.t. y and x, z are constants.

$f_y(x,y,z)=4x\cos (y-z)\dfrac{\partial}{\partial y}(y-z)$

$f_y(x,y,z)=4x\cos (y-z)$

Differentiate partially w.r.t. z and x, y are constants.

$f_z(x,y,z)=4x\cos (y-z)\dfrac{\partial}{\partial z}(y-z)$

$f_z(x,y,z)=4x\cos (y-z)(-1)$

$f_z(x,y,z)=-4x\cos (y-z)$

Therefore, the first partial derivatives of the function are $f_x(x,y,z)=4\sin (y-z), f_x(x,y,z)=4x\cos (y-z)\text{ and }f_z(x,y,z)=-4x\cos (y-z)$ .

4 0

3 years ago

On a coordinate plane, parallelogram A B C D has points (3, 6), (6, 5), (5, 1), and (2, 2).

Vlad1618 [11]

Answer:

Area of parallelogram ABCD=13.05=13 Sq.Units

Step-by-step explanation:

Given;

A(3,6) B(6,5) C(5,1) and D(2,2)

are points for parallelogram

To Find:

Area of Parallelogram ABCD

Solution:

By using distance formula we can calculate for each length of parallelogram

But by property of parallelogram

Opposite side are parallel and equal in length

So AB|| DC i.e AB=DC

And AC|| BD i.e BD=AC

Hence I.e Dist(AB)=Dist(DC)

Now construct the ABCD parallelogram ,on graph so as to find angle made by parallelogram with plane .

(Refer the attachment)

Now

Distance of AD=Sqrt[(2-3)^2+(2-6)^2]

=Sqrt[1+16]

=4.123

Similarly for AB=Sqrt[(6-3)^2+(5-6)^2]

=Sqrt[9+1]

=3.16

ABOVE VALUES ARE SAME AS GRAPH (REFER THE ATTACHMENT)

Now ,angle made by parallelogram with plane and it is 90 degree i.e the

Now Area of parallelogram(ABCD)=a*b*sinФ

here a=4.123 units and b=3.16 units and Ф=90

Area of parallelogram=3.167*4.123*sin90

=3.167*4.123

=13.05 sq. units

3 0

2 years ago

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What is the absolute value of -1+3i

Ierofanga [76]

Answer:

bsdjsds

Step-by-step explanation:

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3 years ago