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kumpel [21]
3 years ago
6

What are the excluded values of the function y= 8/x^2-25

Mathematics
2 answers:
Blababa [14]3 years ago
6 0

Answer:

  8

——

 x2

Step-by-step explanation:

Equation at the end of step  1  :

        8    

 y -  (—— -  25)  = 0  

       x2    

Step  2  :

Rewriting the whole as an Equivalent Fraction :

2.1   Subtracting a whole from a fraction

Rewrite the whole as a fraction using  x2  as the denominator :

         25     25 • x2

   25 =  ——  =  ———————

         1        x2    

Equivalent fraction : The fraction thus generated looks different but has the same value as the whole

Common denominator : The equivalent fraction and the other fraction involved in the calculation share the same denominator

Adding fractions that have a common denominator :

2.2       Adding up the two equivalent fractions

Add the two equivalent fractions which now have a common denominator

Combine the numerators together, put the sum or difference over the common denominator then reduce to lowest terms if possible:

8 - (25 • x2)     8 - 25x2

—————————————  =  ————————

     x2              x2    

Equation at the end of step  2  :

      (8 - 25x2)

 y -  ——————————  = 0  

          x2    

Step  3  :

Rewriting the whole as an Equivalent Fraction :

3.1   Subtracting a fraction from a whole

Rewrite the whole as a fraction using  x2  as the denominator :

         y     y • x2

    y =  —  =  ——————

         1       x2  

Trying to factor as a Difference of Squares :

3.2      Factoring:  8 - 25x2  

Theory : A difference of two perfect squares,  A2 - B2  can be factored into  (A+B) • (A-B)

Proof :  (A+B) • (A-B) =

        A2 - AB + BA - B2 =

        A2 - AB + AB - B2 =

        A2 - B2

Note :  AB = BA is the commutative property of multiplication.

Note :  - AB + AB equals zero and is therefore eliminated from the expression.

Check :  8  is not a square !!

Ruling : Binomial can not be factored as the

difference of two perfect squares

Adding fractions that have a common denominator :

3.3       Adding up the two equivalent fractions

y • x2 - ((8-25x2))     yx2 + 25x2 - 8

———————————————————  =  ——————————————

        x2                    x2      

Trying to factor a multi variable polynomial :

3.4    Factoring    yx2 + 25x2 - 8  

Try to factor this multi-variable trinomial using trial and error  

Factorization fails

Equation at the end of step  3  :

 yx2 + 25x2 - 8

 ——————————————  = 0  

       x2      

Step  4  :

When a fraction equals zero :

4.1    When a fraction equals zero ...

Where a fraction equals zero, its numerator, the part which is above the fraction line, must equal zero.

Now,to get rid of the denominator, Tiger multiplys both sides of the equation by the denominator.

Here's how:

 yx2+25x2-8

 —————————— • x2 = 0 • x2

     x2    

Now, on the left hand side, the  x2  cancels out the denominator, while, on the right hand side, zero times anything is still zero.

The equation now takes the shape :

  yx2+25x2-8  = 0

Solving a Single Variable Equation :

4.2     Solve   yx2+25x2-8  = 0

Blizzard [7]3 years ago
4 0

Answer:

I believe it's B.)5 and -5

Step-by-step explanation:

Hope this helps :))

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General Formulas and Concepts:

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right  

Equality Properties

  • Multiplication Property of Equality
  • Division Property of Equality
  • Addition Property of Equality
  • Subtraction Property of Equality

<u>Algebra I</u>

Coordinate Planes

  • Coordinates (x, y) → (s, P)

Functions

  • Function Notation

Terms/Coefficients

  • Factoring/Expanding

Quadratics

<u>Algebra II</u>

Coordinate Planes

  • Maximums/Minimums

<u>Calculus</u>

Derivatives

  • Derivative Notation

Derivative Property [Multiplied Constant]:                                                           \displaystyle \frac{d}{dx} [cf(x)] = c \cdot f'(x)

Derivative Property [Addition/Subtraction]:                                                         \displaystyle \frac{d}{dx}[f(x) + g(x)] = \frac{d}{dx}[f(x)] + \frac{d}{dx}[g(x)]  

Basic Power Rule:

  1. f(x) = cxⁿ
  2. f’(x) = c·nxⁿ⁻¹

1st Derivative Test - tells us where on the function f(x) does it have a relative maximum or minimum

  • Critical Numbers

Step-by-step explanation:

<u>Step 1: Define</u>

<em>Identify</em>

\displaystyle P = \frac{-1}{10}s^3 + 6s^2 + 400

<u>Step 2: Differentiate</u>

  1. [Function] Derivative Property [Addition/Subtraction]:                               \displaystyle P' = \frac{dP}{ds} \bigg[ \frac{-1}{10}s^3 \bigg] + \frac{dP}{ds} [ 6s^2 ] + \frac{dP}{ds} [ 400 ]
  2. [Derivative] Rewrite [Derivative Property - Multiplied Constant]:               \displaystyle P' = \frac{-1}{10} \frac{dP}{ds} \bigg[ s^3 \bigg] + 6 \frac{dP}{ds} [ s^2 ] + \frac{dP}{ds} [ 400 ]
  3. [Derivative] Basic Power Rule:                                                                     \displaystyle P' = \frac{-1}{10}(3s^2) + 6(2s)
  4. [Derivative] Simplify:                                                                                     \displaystyle P' = -\frac{3s^2}{10}  + 12s

<u>Step 3: 1st Derivative Test</u>

  1. [Derivative] Set up:                                                                                       \displaystyle 0 = -\frac{3s^2}{10}  + 12s
  2. [Derivative] Factor:                                                                                       \displaystyle 0 = \frac{-3s(s - 40)}{10}
  3. [Multiplication Property of Equality] Isolate <em>s </em>terms:                                   \displaystyle 0 = -3s(s - 40)
  4. [Solve] Find quadratic roots:                                                                         \displaystyle s = 0, 40

∴ <em>s</em> = 0, 40 are our critical numbers.

<u>Step 4: Find Profit</u>

  1. [Function] Substitute in <em>s</em> = 0:                                                                       \displaystyle P(0) = \frac{-1}{10}(0)^3 + 6(0)^2 + 400
  2. [Order of Operations] Evaluate:                                                                   \displaystyle P(0) = 400
  3. [Function] Substitute in <em>s</em> = 40:                                                                     \displaystyle P(40) = \frac{-1}{10}(40)^3 + 6(40)^2 + 400
  4. [Order of Operations] Evaluate:                                                                   \displaystyle P(40) = 3600

We see that we will have a bigger profit when we spend <em>s</em> = $40.

∴ The maximum profit is $3600.

∴ The point of diminishing returns is ($40, $3600).

Topic: AP Calculus AB/BC (Calculus I/I + II)

Unit: Differentiation (Applications)

5 0
2 years ago
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