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il63 [147K]
3 years ago
13

Determine the center and the diameter of the circle with the equation. x^2-6x+y^2+8y=24

Mathematics
1 answer:
Arisa [49]3 years ago
6 0

Answer:

The center of the circle is (3, -4)

The diameter of the circle is 2

Step-by-step explanation:

The given equation of the circle is x² - 6·x + y² + 8·y = 24

The general form of the equation of a circle is x² + y² + 2·g·x + 2·f·y + c = 0

The center of the circle = (-g, -f)

The radius of the circle = √(g² + f² - c)

By comparing the given equation of the circle with the general form of the equation of a circle, we have;

2·g = -6, 2·f = 8, and c = 24

From 2·g = -6, we get;

∴ g = -6/2 = -3

g = -3

from 2·f = 8, we get;

∴ f = 8/2 = 4

f = 4

Therefore;

The center of the circle, (-g, -f) = (-(-3), -4) = (3, -4)

The center of the circle = (3, -4)

The radius of the circle, r = √(g² + f² - c) = √((-3)² + 4² - 24) = 1

The diameter of the circle, d = 2×r = 2 × 1 = 2

The diameter of the circle = 2.

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weqwewe [10]

Answer: 21y^5-28y^4+49y^3

If the remainder isn't necessarily zero, we add C_1y^2+C_2y+C_3, which covers all possible remainders when dividing by a polynomial with leading term in y^3.


Step-by-step explanation:

(3y^2-4y+7)(7y^3) =

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3 years ago
How to write 3 9/100 as a decimal?
Artemon [7]
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4 years ago
Read 2 more answers
PLEASE HELP ASAP! URGENT!
Mademuasel [1]
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4 years ago
HELP ME ASAP <br> 1. (-4/3)-(-3/2) <br> 2 -3.9-8.9<br> 3 2.9-(-9.4)
solmaris [256]
Here is your first answer:

First find whats common which is 6:

-4×2=-8
3×2=6
-3×3=-9
2×3=6

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Here is your second answer:

First use KCC to Chang the equation into...

-3.9
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Then add:

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Here is your third answer:

First change the equation (KCC):

2.9
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There are your answers:
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