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3 years ago

How Can You Prove The Triangles Are Congruent?

Mathematics

1 answer:

german3 years ago

3 0

You can prove they're congruent by SAS Postulate. You see that there are two alternate interior angels and one pair of congruent sides.

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Plz help

Semenov [28]

This is a classic example of Scientific Notation.
5.3 x 10^5 actually equals 530,000
3.8 x 10^4 actually equals 38,000
Since it is asking for the sum of the numbers you are adding.
Your new equation look like this:
530,000 + 38,000
= 568,000
now all you have to do is count the decimal points. You start from the end zero and count the spaces in between until you get to the tenths place. (Right behind the first number) There are 5
So your answer will be:
B. 5.68 x 10^5.

5 0

3 years ago

Diagram shows a section of a bridge between the points A and K. The length of line segment is 640 meters. ∆ABC, ∆CDF, and ∆FJK a

Marta_Voda [28]

AK = 640
Δ ABC and ΔFJK are similar. They are small triangles.
ΔCDF is the big triangle.

640 / 2 = 320 m= CF
AC & FK= 320/2 = 160 m each

2AC = CF = 2FK
2(160) = 320 = 2(160)

BG = 20 m

20/160 = x / 320
20*320 = 160x
6400 = 160x
6400/160 = x
40 = x

Area of CDF = (40 m * 320 m)/2 = 12,800 / 2= 6,400 m²

3 0

3 years ago

in the number line shown below,which lettered point represents the quotient of 1 7/8 of divided by 1/2

emmasim [6.3K]

Where is the number line I can't solve without it

5 0

3 years ago

Read 2 more answers

Anyone can help me solve this equation using cross multiplying

Natali5045456 [20]

9514 1404 393

Answer:

x = 1 or 5

Step-by-step explanation:

The notion of "cross-multiplying" is the idea that the numerator on the left is multiplied by the denominator on the right, and the numerator on the right is multiplied by the denominator on the left. This looks like ...

$\displaystyle \frac{x-1}{7}=\frac{2x-2}{3x-1}\ \longrightarrow\ (x-1)(3x-1)=(7)(2x-2)$

Then the solution proceeds by eliminating parentheses, and solving the resulting quadratic equation.

$3x^2-4x+1=14x-14\\\\3x^2-18x+15=0\qquad\text{subtract $14x-14$}\\\\x^2-6x+5=0 \qquad\text{divide by 3}\\\\(x-1)(x-5)=0\qquad\text{factor}\\\\x\in\{1,5\}$

_____

Comment on "cross multiply"

Like a lot of instructions in Algebra courses, the idea of "cross multiply" describes what the result looks like. It doesn't adequately describe how you get there. The one and only rule in solving Algebra problems is "whatever is done to one side of the equation must also be done to the other side of the equation." If you multiply one side by one thing and the other side by a different thing, you are violating this rule.

What looks like "cross multiply" is really "multiply by the product of the denominators and cancel like terms from numerator and denominator." Here's what that looks like with the intermediate steps added.

$\displaystyle \frac{x-1}{7}=\frac{2x-2}{3x-1}\\\\\frac{x-1}{7}\times7(3x-1)=\frac{2x-2}{3x-1}\times7(3x-1)\\\\(x-1)(3x-1)=(2x-2)(7)\qquad\textit{looks like}\text{ cross multiply}$

8 0

2 years ago

I need help. once again. bahahaha

katrin [286]

Answer:

letters d. and e.

5 0

3 years ago