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3 years ago

How Can You Prove The Triangles Are Congruent?

Mathematics

1 answer:

german3 years ago

3 0

You can prove they're congruent by SAS Postulate. You see that there are two alternate interior angels and one pair of congruent sides.

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MariettaO [177]

Answer:

Similarity: sinusoidal function has the same general shape as a sine or cosine function. Differences: y = sin x and y = cos x

Step-by-step explanation:

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2 years ago

Which statement is true?

Nina [5.8K]

Answer: I think the answer is 1 in my opinion but not sure

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3 years ago

12a^3b^2 +18a²b^2 – 12ab^2<br> Factor completely

AleksAgata [21]

The factorization of 12a^3b^2 +18a²b^2 – 12ab^2 is $6 a b^{2}(a+2)(2 a-1)$

<u>Solution:</u>

Given, expression is $12 a^{3} b^{2}+18 a^{2} b^{2}-12 a b^{2}$

We have to factorize the given expression completely.

Now, take the expression

$12 a^{3} b^{2}+18 a^{2} b^{2}-12 a b^{2}$

Taking $b^2$ as common term,

$b^{2}\left(12 a^{3}+18 a^{2}-12 a\right)$

Taking "a" as common term,

$b^{2}\left(a\left(12 a^{2}+18 a-12\right)\right)$

Taking "6" as common term,

$b^{2}\left(a\left(6\left(2 a^{2}+3 a-2\right)\right)\right)$

Splitting "3a" as "4a - a" we get,

$b^{2}\left(a\left(6\left(2 a^{2}+4 a-a-2\right)\right)\right)$

$\begin{array}{l}{b^{2}(a(6(2 a(a+2)-1(a+2))))} \\\\ {b^{2}(a(6((a+2) \times(2 a-1))))} \\\\ {6 a b^{2}(a+2)(2 a-1)}\end{array}$

Hence, the factored form of given expression is $6 a b^{2}(a+2)(2 a-1)$

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2 years ago

Really need help with this

IrinaVladis [17]

Answer:

36.89°

Step-by-step explanation:

tan x = 15/20=3/4

x = 36.89

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1 year ago

Yousef buys 40 tokens at the carnival. He gives his sister tokens for 5 kiddie rides. He wants to use the remaining token for th

lawyer [7]

Answer:

5 rides

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2 years ago