The area of A'B'C is 6.25 times the area of ABC. Also it wouldnt hurt the report the guy below who's obviously milking points.
The complete question in the attached figure
we have that
<span>m∠4=68°
we know that
</span>m∠4 and m∠3 are supplementary angles
so
m∠3=180-m∠4----- m∠3=180-68------> m∠3=112°
m∠3 = m∠2 --------> by alternate interior angles
so
m∠2=112°
m∠1 = m∠4 --------> by alternate exterior angles
so
m∠1=68°
m∠5 = m∠4---------> by corresponding angles
so
m∠5=68°
the answers arem∠1=68°m∠2=112m∠3=112°m∠5=68°
Answer:
it is 2
Step-by-step explanation:
i think it is
Answer:
I think it's
Step-by-step explanation:
73.70×3
221.1