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Ivan
3 years ago
11

Help: theoretical and experimental probability

Mathematics
1 answer:
Natalija [7]3 years ago
5 0
D is the right one, in all these suggestions , the number cube is rolled 1 time. 
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Pls help me!! thank you!!
klasskru [66]

Full working out shown from step 1 to last.

follow it and you get 24 square feet as final answer. Good luck in other questions!!!

3 0
2 years ago
What is the exact value for the expression the square root of 189. − the square root of 21. + the square root of 84.? Simplify i
klemol [59]
<span>It's 4 the square root of 21</span>
7 0
3 years ago
I need help ASAP! Can anyone please check my work?
STALIN [3.7K]

A = event the person got the class they wanted

B = event the person is on the honor roll

P(A) = (number who got the class they wanted)/(number total)

P(A) = 379/500

P(A) = 0.758

There's a 75.8% chance someone will get the class they want

Let's see if being on the honor roll changes the probability we just found

So we want to compute P(A | B). If it is equal to P(A), then being on the honor roll does not change P(A).

---------------

A and B = someone got the class they want and they're on the honor roll

P(A and B) = 64/500

P(A and B) = 0.128

P(B) = 144/500

P(B) = 0.288

P(A | B) = P(A and B)/P(B)

P(A | B) = 0.128/0.288

P(A | B) = 0.44 approximately

This is what you have shown in your steps. This means if we know the person is on the honor roll, then they have a 44% chance of getting the class they want.

Those on the honor roll are at a disadvantage to getting their requested class. Perhaps the thinking is that the honor roll students can handle harder or less popular teachers.

Regardless of motivations, being on the honor roll changes the probability of getting the class you want. So Alex is correct in thinking the honor roll students have a disadvantage. Everything would be fair if P(A | B) = P(A) showing that events A and B are independent. That is not the case here so the events are linked somehow.

8 0
3 years ago
The High Roller, a giant ferris wheel in Las Vagas, casts a 242-foot shadow. A 6’3” tall man standing nearby casts a 2 3/4-foot
Ira Lisetskai [31]

Answer:

550ft

Step-by-step explanation:

Simple napkin math, so you know what both shadows are you need to find how tall the High Roller is we will use X for this.

\frac{242ft}{6'3"}  x \frac{x}{2'9"}

Im not 100% I set it up right but essentially 242 divided by 2'9" and that equals 88

Take 88 and multiply that by 6'3" and you get your Height for the High Roller

What I did their was I scaled the humans height to that of the High Roller dividing it gives you a number you can use to scale the height of that human to how it should scale to the High Roller, which is why I took 88 and multiplied it by the human's height.

Hope this helped :)

6 0
3 years ago
If Tom Parsons traveled 232 miles in 4 hours, how many miles should he travel in 8
sesenic [268]

Answer:

464

Step-by-step explanation:

7 0
3 years ago
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