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Artyom0805 [142]
3 years ago
12

Evaluate the expression for n=8 7(n-7)+17

Mathematics
1 answer:
omeli [17]3 years ago
5 0

Answer:

24

Step-by-step explanation:

7(n - 7) + 17        Substitute 8 for n

7(8 - 7) + 17        Subtract 8 - 7    

7(1) + 17               Multiply 7 x 1

7 + 17                   Add

24

If this answer is correct, please make me Brainliest!

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Answer:

6 or 3mL/hr, probably 3mL/hr

Step-by-step explanation:

If dopamine makes up half of the solution then you half the total mL/hr to 3. If it is the whole solution then it tells you the answer (6mL/hr). I'm not sure if the question is poorly worded or just how you typed it but it would be easier to answer if it was clearer.

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Given frequent itemset l and subset s of l, prove that the confidence of the rule "s’ => (l - s’)" cannot be more than the co
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the answer is I

Step-by-step explanation:

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4 years ago
[PICTURE ATTACHED] help asap
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40- 15/t

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4 0
3 years ago
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Write the equation of the line that passes through each pair of points in slope-intercept form. This is worth 3 points. You have
LekaFEV [45]
(0,5)(3,-1)
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slope(m) = -2
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2. Inflation is at a rate of 7% per year. Evan's favorite bread now costs $1.79. What did it cost 10 years ago? How long
Makovka662 [10]

Answer:

It cost $0.91 10 years ago.

It takes 10.24 years for the cost of bread to double.

Step-by-step explanation:

The equation for the price of bread after t years has the following format:

P(t) = P(0)(1+r)^{t}

In which P(0) is the current price, and r is the inflation rate, as a decimal.

If we want to find the price for example, 10 years ago, we find P(-10).

Inflation is at a rate of 7% per year. Evan's favorite bread now costs $1.79.

This means that r = 0.07, P(0) = 1.79. So

P(t) = P(0)(1+r)^{t}

P(t) = 1.79(1+0.07)^{t}

P(t) = 1.79(1.07)^{t}

What did it cost 10 years ago?

P(-10) = 1.79(1.07)^{-10} = 0.91

It cost $0.91 10 years ago.

How long before the cost of the bread doubles?

This is t for which P(t) = 2P(0) = 2*1.79. So

P(t) = 1.79(1.07)^{t}

2*1.79 = 1.79(1.07)^{t}

(1.07)^{t} = 2

\log{(1.07)^{t}} = \log{2}

t\log{1.07} = \log{2}

t = \frac{\log{2}}{\log{1.07}}

t = 10.24

It takes 10.24 years for the cost of bread to double.

5 0
3 years ago
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