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Svetllana [295]
3 years ago
10

Can someone help me on this one Please

Mathematics
1 answer:
Mumz [18]3 years ago
6 0
X-4y=1
2x+y=11
ok so you have x-4y=1 and 2x+y=11
3x-3y=12 is your answer
You might be interested in
Perform the indicated operation.<br> 1 1/6 + 7 3/6 =<br><br> I HAVE 5 MINUTES!!!
gizmo_the_mogwai [7]

Answer:

1 1/6 - 7 3/6 = -19/

3

= -6 1/

3

≅ -6.3333333

Step-by-step explanation:

Conversion a mixed number 1 1/

6

to a improper fraction: 1 1/6 = 1 1/

6

= 1 · 6 + 1/

6

= 6 + 1/

6

= 7/

6

To find new numerator:

a) Multiply the whole number 1 by the denominator 6. Whole number 1 equally 1 * 6/

6

= 6/

6

b) Add the answer from previous step 6 to the numerator 1. New numerator is 6 + 1 = 7

c) Write a previous answer (new numerator 7) over the denominator 6.

One and one sixth is seven sixths

Conversion a mixed number 7 3/

6

to a improper fraction: 7 3/6 = 7 3/

6

= 7 · 6 + 3/

6

= 42 + 3/

6

= 45/

6

To find new numerator:

a) Multiply the whole number 7 by the denominator 6. Whole number 7 equally 7 * 6/

6

= 42/

6

b) Add the answer from previous step 42 to the numerator 3. New numerator is 42 + 3 = 45

c) Write a previous answer (new numerator 45) over the denominator 6.

Seven and three sixths is forty-five sixths

Subtract: 7/

6

- 45/

6

= 7 - 45/

6

= -38/

6

= 2 · -19/

2 · 3

= -19/

3

For adding, subtracting, and comparing fractions, it is suitable to adjust both fractions to a common (equal, identical) denominator. The common denominator you can calculate as the least common multiple of both denominators - LCM(6, 6) = 6. In practice, it is enough to find the common denominator (not necessarily the lowest) by multiplying the denominators: 6 × 6 = 36. In the next intermediate step, the fraction result cannot be further simplified by canceling.

In words - seven sixths minus forty-five sixths = minus nineteen thirds.

4 0
3 years ago
What do 15/43 = in simplest form
alina1380 [7]
Idk I’m sorryyy I’m having trouble tooo
5 0
3 years ago
Read 2 more answers
Totsakan school is selling tickets to a choral performance on the first day of ticket sales the school sold 10 senior tickets an
ohaa [14]

Given :

On the first day of ticket sales the school sold 10 senior tickets and 1 child ticket for a total of $85 .

The school took in $75 on the second day by selling 5 senior citizens tickets and 7 child tickets.

To Find :

The price of a senior ticket and the price of a child ticket.

Solution :

Let, price of senior ticket and child ticket is x and y respectively.

Mathematical equation of condition 1 :

10x + y = 85    ...1)

Mathematical equation of condition 2 :

5x + 7y = 75    ...2)

Solving equation 1 and 2, we get :

2(2) - (1)   :

2( 5x + 7y - 75 ) - ( 10x +y - 85 ) = 0

10x + 14y - 150 - 10x - y + 85 = 0

13y = 65

y = 5

10x - 5 = 85

x = 8

Therefore, price of a senior ticket and the price of a child ticket $8 and $5.

Hence, this is the required solution.

 

5 0
3 years ago
If (x+1,10)=(4,2y) then find the value of x &amp; y
lawyer [7]

Answer:

<h2><em><u>x</u></em><em><u> </u></em><em><u>=</u></em><em><u> </u></em><em><u>3</u></em><em><u> </u></em><em><u> </u></em><em><u>&</u></em><em><u> </u></em><em><u>y</u></em><em><u> </u></em><em><u>=</u></em><em><u> </u></em><em><u>5</u></em></h2>

Step-by-step explanation:

<h3><em><u>Given</u></em><em><u>, </u></em></h3>

(x+1, 10) = (4, 2y)

<u>First</u><u> </u><u>x</u><u> </u><u>coordinate</u><u>, </u>

x + 1 = 4

=> x = 4 - 1

=> <em>x = 3 (Ans) (i)</em>

<u>Second</u><u> </u><u>y</u><u> </u><u>coordinate</u><u>, </u>

10 = 2y

=  > y =  \frac{10}{2}

=> <em>y</em><em> </em><em>=</em><em> </em><em>5</em><em> </em><em>(</em><em>Ans</em><em>)</em><em> </em><em>(</em><em>ii</em><em>)</em>

3 0
3 years ago
A physics class has 40 students. Of​ these, 17 students are physics majors and 16 students are female. Of the physics​ majors, s
Snezhnost [94]

Answer:

Probability of female   P(f)   =  0,575    or   57,5  %

Probability of physic majors  P = 0,425 or  42,5 %

Step-by-step explanation:

a) Probability that a random selected student is female:

Let call P(f)  such probability   is  P(f1)  + P(f2)

we have to evaluate 2 branch of the tree, working as follows

1.Probability of students as physics major is P(f1)

17/40     and after that the probability of student physics majors being female is 7/17, Therefore for that side we have probability

P(f1)  = ( 17/40)* (7/17)    =  119/680

2.-Probability of students as female from 40 student is

16/40

Then   P(f)  = ( 119/680) + 16/40       P(f)  = 391/680

P(f)  = 0,575    or    57,5%

b) Probability of physics majosr is:

P(pm)  =  17/40

P(pm)  =  0,425     or   42,5 %

4 0
3 years ago
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