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shtirl [24]
3 years ago
15

Find two positive real numbers whose product is a maximum. the sum is 80

Mathematics
2 answers:
Ainat [17]3 years ago
6 0
Xy=max
x+y=80
minus x both sides to solve for y
y=80-x
subsitute

(x)(80-x)=max
80x-x²=max
take the derivitive
80-2x=max'
find where it equalt 0
80-2x=0
80=2x
40=x
at x=40
then y=80-40=40

the numbers are 40 and 40


Eduardwww [97]3 years ago
4 0
Let's say the numbers are "a" and "b"

thus \bf y=ab\qquad 
\begin{cases}
a+b=80\\
b=80-a
\end{cases}\implies y=a(80-a)\implies y=80a-a^2\\\\
-----------------------------\\\\
\cfrac{dy}{da}=80-2a

set the derivative to 0, and check the critical points, there's only one anyway

and do a first-derivative test, to see if it's a maximum
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Step-by-step explanation:

Process

1.- Find the value of x using the large right triangle, remember that the sum of the internal angles in a triangle equals 180°.

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