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Allisa [31]
3 years ago
12

Historic and Current real life examples

Biology
1 answer:
alexira [117]3 years ago
8 0
<span>Historic and Current are real life examples because of every language </span><span />
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Explain why plants along the road often die after the road is sprayed with a salt solution to melt ice
vovangra [49]

Explanation:

The salt solution is meant to lower the ice melting point hence keep most of the water from turning into ice even at zero degrees temperatures. The salts are dissolved in the water to form a salty solution that percolates the ground and reach plant roots. Because the salty water is hypertonic (more concentrated) to the cell cytoplasm of the plant roots, water is drawn from the plant by osmosis. This is the reversal of normal plant root absorption of water from the soil. This causes the plant root to wither and subsequently the whole plant to die. Remember in osmosis, water moves from the less concentrated solution to the more concentrated solution through a semipermeable membrane.

Learn More:

For more on osmosis check out;

brainly.com/question/6320563

brainly.com/question/13418400

#LearnWithBrainly

5 0
3 years ago
An amoeba reproduces by splitting itself into two amoebas. This means that the original amoeba dies and its two offspring live o
Naddika [18.5K]

Answer:

If one amoeba dies then two amoeba get born:

at different stages of the generations of the amoeba it changes accordingly and the died amoeba numbers are also change in the given manner :

          stages    dies                          born

          I               1                                2

          II              2^{1}           4 = 2^{2}

          III              2^{2}          8 = 2^{3}

At  n^{th} =  2^{n}    2^{n+1}

By the geometric series formula:

 1+a^{1}+ a^{2}+ a^{3}...+ a^{n}=\frac{a^{n+1} }{a^-1} }

so,  1+2^{1}+ 2^{2}+ 2^{3}...+ 2^{n}=\frac{2^{n+1} }{2^-1} }

Thus, total amoeba died = 2^{n+1}-1

        total amoeba died+1 = 2^{n+1} (born).... hence prooved

5 0
3 years ago
This same technique was used to create dolly the sheep, the first cloned mammal, in 1996. dolly was developed from an egg cell t
Umnica [9.8K]
Dolly was a female fin Dorset sheep,
Although it has been claimed that dolly had 3 mothers. one provided the egg, another the DNA, and a third carried the cloned embryo to term.
So therefore, dolly has the genes of different species of sheeps.

Hope this helped!
5 0
3 years ago
[Chapter 3-4] A cross was carried out between the following two pureline parental strains:Parent 1: A/A; b/b; D/D; e/e; F/FParen
andrew-mc [135]

Answer:

Following the selfing of the F1 from the cross between the two parental strains, what proportion of the F2 individuals will phenotypically resemble either one of the two parental lines?

= 7.03% of F2 progeny will resemble parent 1

= 2.34% of F2 progeny will resemble parent 2.

Explanation:

Parent 1: AA; b/b; D/D; e/e; F/F

Parent 2: a/a; B/B; d/d; E/E; f/f

F1 Progeny: A/a; B/b; D/d; E/e; F/f

knowing that the F1 progeny is selfed, the possible gamete outcomes are:

ABDeF , ABDEf, ABdeF, ABdEf

AbDeF , AbDEf , AbdeF , AbdEf

aBDeF , aBDEf , aBdeF , aBdEf

abDeF , abDEf , abdeF , abdEf

All gametes are either eF or Ef (the two parental genotypes) and never EF or ef.

At the A, B and D loci, the F1 are heterozygotes. Therefore, in the F2 progeny, for each locus, 3/4 of the progeny will have the dominant trait while 1/4 will have the recessive phenotype. Further, 1/2 of all F2 progeny will have the haplotype eF and the other half will be Ef.

<u>Proportion of progeny resembling Parent 1: </u>

Parent 1 has the Phenoytpe AbDeF. As previously discussed, 3/4th of all F2 progeny has the phenotype A, 1/4th of F2 progeny has the phenotype b, 3/4th of F2 progeny has the phenotype D and 1/2 of F progeny has the phenotype eF.

Thus, the proportion of progeny resembling Parent 1

= 3/4 x 1/4 x 3/4 x 1/2 = 0.0703125

= 7.03% of F2 progeny will resemble parent 1.

<u>Proportion of progeny resembling Parent 2</u>:

Parent 2 has the Phenoytpe aBdEf. As previously discussed, 1/4th of all F2 progeny has the phenotype a, 3/4th of F2 progeny has the phenotype B, 1/4th of F2 progeny has the phenotype d and 1/2 of F progeny has the phenotype Ef.

Thus, Proportion of progeny resembling parent 2

= 1/4 x 3/4 x 1/4 x 1/2 = 0.0234375

= 2.34% of F2 progeny will resemble parent 2.

7 0
3 years ago
Explain a scenario in which secondary succession would occur.
andrey2020 [161]

Answer:

In secondary succession, a previously occupied area is re-colonized following a disturbance that kills much or all of its community. A classic example of secondary succession occurs in oak and hickory forests cleared by wildfire. Wildfires will burn most vegetation and kill animals unable to flee the area.

4 0
3 years ago
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