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3 years ago

The length of a shadow of a building is

1 answer:

6 0

H^2=x^2+y^2

35^2=29^2+y^2

y^2=35^2-29^2

y^2=384

y=√384

y≈19.60 m (to the nearest hundredth of a meter, or nearest centimeter)

You might be interested in

A certain company assigns employees to offices in such a way that some of the offices can be empty and more than one employee ca

vladimir2022 [97]

Answer:

There are 8 ways.

Step-by-step explanation:

For each employee there are two possibilities: first office and second office.

Therefore,

the number of ways the company can assign 3 employees to 2 different offices will be :

$2^{3}$ = 8

We can also look at this problem like suppose ABC are employees.

We can arrange them like -

0 ABC

ABC 0

AB C

BC A

CA B

A BC

B CA

C AB

So, there are total 8 WAYS.

4 0

3 years ago

Find the Laplace transformation of each of the following functions. In each case, specify the values of s for which the integral

MAVERICK [17]

Answer:

a. $\frac {2} {s-1}$ converges to s> 1.

b. $\frac{3}{e^3 \left(s-5 \right)}$ converges to s> 5.

c. $- \frac {2}{s + 3}$ converges to s> - 3.

d. $\frac {s}{s^2 + 25}$ converges to s> 0.

e. $\frac {10} {s^2 + 1}$ converges even s> 0.

f. $\frac {12}{s^2 + 4}$ converges to s> 0.

g. $-\frac {5\left(\cos\left (1\right) s-2 \sin\left(1\right)\right)}{s^2 + 4}$ converges to s> 0.

h. $\frac {1} {s ^ 2 + 4}$ converges to s> 0.

Step-by-step explanation:

a. $L \left\{2e^t \right\} = 2L \left\{e^t \right\} = 2 \cdot \frac {1} {s-1} = \frac {2} {s-1}$ converges to s> 1.

b. $L \left\{3e^{5t-3} \right\} = 3e^{-3} L \left\{e^{5t} \right\} = 3e^{-3} L \left\{e^{5t} \right\} = \frac{3}{e^3 \left(s-5 \right)}$ converges to s> 5.

c. $L \left\{-2e^{-3t} \right\} = -2L \left\{e^{-3t} \right\} = - \frac {2}{s + 3}$ converges to s> - 3.

d. $L \left\{\cos\left (5t \right)\right\} = \frac {s}{s^2 + 25}$ converges to s> 0.

e. $L \left\{10 \sin\left(t\right)\right\} = 10L\left\{\sin\left(t\right)\right\} = \frac {10} {s^2 + 1}$ converges even s> 0.

f. $L \left\{6\sin \left(2t \right) \right\} = 6L\left\{\sin\left (2t\right)\right\} = \frac {12}{s^2 + 4}$ converges to s> 0.

g. $L \left\{-5\cos\left(2t + 1\right) \right\} = -5L\left\{\cos\left(2t + 1 \right)\right\} = -\frac {5\left(\cos\left (1\right) s-2 \sin\left(1\right)\right)}{s^2 + 4}$ converges to s> 0.

h. $L\left\{\sin \left(t\right)\cos \left(t\right)\right\} = L\left\{\sin\left(2t\right)\frac{1}{2}\right\} =\frac{1}{2}\cdot \frac{2}{s^2+4} = \frac {1} {s ^ 2 + 4}$ converges to s> 0.

7 0

3 years ago

How do I solve −6 + 9(8 − 2b) using distributive property or combining like terms.

Levart [38]

Answer:

66-18b

Step-by-step explanation:

-6+72-18b

66-18b

solving for b

b=3.66 or 3 and 2/3

7 0

3 years ago

BRAINLIEST PLEASE HELP np<br> If f(x)=-x^2+6x-1 and g(x)=3x^2-4x-1, find (f+g)(x)

raketka [301]

Answer:

$\large\boxed{B.\ (f+g)(x)=2x^2+2x-2}$

Step-by-step explanation:

$f(x)=-x^2+6x-1\\\\g(x)=3x^2-4x-1\\\\(f+g)(x)=f(x)+g(x)\\\\\text{substitute:}\\\\(f+g)(x)=(-x^2+6x-1)+(3x^2-4x-1)\\\\(f+g)(x)=-x^2+6x-1+3x^2-4x-1\qquad\text{combine like terms}\\\\(f+g)(x)=(-x^2+3x^2)+(6x-4x)+(-1-1)\\\\(f+g)(x)=2x^2+2x-2$

8 0

3 years ago

Can you please solve and explain how

Karolina [17]

First, it would help to simplify each side more:

Left side: 36 + 3(4x - 9) = 36 + 12x - 27 = 12x + 9

Right side: c(2x + 1) + 25 = 2cx + c + 25

Write the simplified equation:

12x + 9 = 2cx + c + 25

Usually when there is no solution, the coefficients of the variable on both sides are the same, so we can make the coefficient if x on the right side into 12:

2cx >>> 12x

Then, c must equal 6 to make this true.

The answer is choice (C).

6 0

3 years ago

Read 2 more answers