Answer:
1. ∠1 = 120°
2. ∠2 = 60°
3. ∠3 = 60°
4. ∠4 = 60°
5. ∠5 = 75°
6. ∠6 = 45°
Step-by-step explanation:
From the diagram, we have;
1. ∠1 and the 120° angle are corresponding angles
Corresponding angles are equal, therefore;
∠1 = 120°
2. ∠2 and the 120° angle are angles on a straight line, therefore they are supplementary angles such that we have;
∠2 + 120° = 180°
∠2 = 180° - 120° = 60°
∠2 = 60°
3. Angle ∠3 and ∠2 are vertically opposite angles
Vertically opposite angles are equal, therefore, we get;
∠3 = ∠2 = 60°
∠3 = 60°
4. Angle ∠1 and angle ∠4 an=re supplementary angles, therefore, we get;
∠1 + ∠4 = 180°
∠4 = 180° - ∠1
We have, ∠1 = 120°
∴ ∠4 = 180° - 120° = 60°
∠4 = 60°
5. let the 'x' and 'y' represent the two angles opposite angles to ∠5 and ∠6
Given that the two angles opposite angles to ∠5 and ∠6 are equal, we have;
x = y
The two angles opposite angles to ∠5 and ∠6 and the given right angle are same side interior angles and are therefore supplementary angles
∴ x + y + 90° = 180°
From x = y, we get;
y + y + 90° = 180°
2·y = 180° - 90° = 90°
y = 90°/2 = 45°
y = 45°
Therefore, we have;
∠4 + ∠5 + y = 180° (Angle sum property of a triangle)
∴ ∠5 = 180 - ∠4 - y
∠5 = 180° - 60° - 45° = 75°
∠5 = 75°
6. ∠6 and y are alternate angles, therefore;
∠6 = y = 45°
∠6 = 45°.
Answer:
The point (0, 6.7) is the point where the ball was launched.
Step-by-step explanation:
The ball was launched from a point 6.7 feet from ground level.
In this scenario (ball tossed toward the goal), the constant c at the end of the function formula gives you the initial position (height).
<span>78.6 is a decimal number, you must name it with the whole part first and then the decimal part as part of tenths, hundredths or what it corresponds. In this case the whole part is 78 and the decimal part is 6/10 which is 6 tenths. Then, the number in words is sevety eight and six tenths.</span>
Answer:
The point is in the 4th quadrant.
Explanation:
Given the ordered pair(4, -5), we have that x = 4 and y = -5. Plotting this point, we'll have;
Note that quadrants are labelled in an anti-clockwise direction with the top right portion of the graph as the 1st quadrant. Looking at the plotted point, we can see that it i in the 4th quadrant.
Answer:

Step-by-step explanation:
The standard charge includes an initial fee and plus an addditional fee for each mile driven and is given by:

The insurance charge is given by:

So, the total charge C will be the sum of the standard charge S and the insurance charge I:

Substitute:

Rearrange:

Add:

And we have acauired our equation relating C to M!