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3 years ago

How to solve these equations

Mathematics

1 answer:

nlexa [21]3 years ago

6 0

All u have to do is plug in the values
68) -(4q) = -(4*-3) =-4*3= -12
70) 5P-6= (5*5)-6 =25-6= 19
72) 7q-7p= 7(-3)-7(5) = -21-35= -56
74)2q/(4p) = 2(-3)/4(5)= -6/20= -3/10

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snow_lady [41]

Answer: 6700 meters

Step-by-step explanation:

From the question given, we are informed that Gephart is traveling from his house to the history museum and that the distance from home to the history museum is six and seven-tenths kilometers.

In order to know the distance in meters

that he will travel to the museum, we have to multiply the convert the distance given in kilometers to meters. This will be:

1000 meters = 1 kilometer

Therefore, 6 7/10km = (6 7/10 × 1000m)

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3 years ago

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11111nata11111 [884]

Here is your answer

$\frac{9}{16} \pi \: {units}^{2}$

REASON:

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, where r is radius

Given

C= (3/2) π

So,

$2\pi \: r = \frac{3}{2}\pi$

$r = \frac{\frac{3}{2}\pi}{2\pi}$

$r = \frac{3}{4}$

Now,

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4 years ago

The speed of the current in a creek is 5 mph. A person clan kayak 3 mi upstream in the same time that it takes him to kayak 13 m

Brut [27]

Answer:

Step-by-step explanation:

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1) if the person's speed in still water is 'v' and the speed of water is 5 (according to the condition), then the upstream speed is 'v-5' and the downstream speed is 'v+5';

2) according to the condition the upstream time and the downstream time are the same, it means t₁=t₂=t, where t₁=upstream time and t₂=downstream time;

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4) according to the items above it is possible to make up the equation of the downstream travel: t(v+5)=13; ⇒ t=13/(v+5);

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$\frac{3}{v-5} =\frac{13}{v+5}; \ => \ v=8.$

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Answer:

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