Answer:
well you should firstcalculate the distance then divide by the primary source and you should be able to get the answer after substituting
Step-by-step explanation:
<span>So
let’s simplify the given situation.
We need to find out how much heavier is 91/8 lbs. compare to 2 5/6 lbs.
Since, it’s a combination of whole number and fraction; we cannot directly
subtract this given equation. We need to convert the two given number into a
fraction.
9 1/8 = 8 x 9 = 72 + 1 = 73, 73 is our numerator and 8 is our denominator
=> 73/8
2 5/6 = 6 x 2 = 12 + 5 = 17, 17 is our numerator and 6 is our denominator
=> 17/6
Now, we have 2 fractions with unlike denominator. In order to get a common
denominator, we have to find their least common factor.
=> <u>73</u> - <u>17 </u> = <u>73 x 6 </u> - <u>17 x 8 </u> <u>
</u> 8 6
8 x 6 6
x 8</span><span>
=> <u>438</u> – <u>136 </u> Now, we
have the same denominator, subtract</span><span>
48 48
=> <u>302 </u> or <u>151</u>
48 24
=> 6 <u>7</u>
24
Therefore 9 1/8 lbs. is 6 7/24 lbs. heavier than 2 5/6 lbs.</span>
If you round 1506 down to 1500, then you can divide that by 2. rounding it down will make it easier.
Given J(1, 1), K(3, 1), L(3, -4), and M(1, -4) and that J'(-1, 5), K'(1, 5), L'(1, 0), and M'(-1, 0). What is the rule that tran
anastassius [24]
(x; y) -> (x - 2; y + 4)
J(1; 1) ⇒ J'(1 - 2; 1 + 4) = (-1; 5)
K(3; 1) ⇒ K'(3 - 2; 1 + 4) = (1; 5)
L(3;-4) ⇒ L'(3 - 2; -4 + 4) = (1; 0)
M(1;-4) ⇒ M'(1 - 2;-4 + 4) = (-1; 0)