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agasfer [191]
3 years ago
11

If the circumference is 3/2 pi what is the area

Mathematics
1 answer:
11111nata11111 [884]3 years ago
8 0

Here is your answer

\frac{9}{16} \pi \:  {units}^{2}

REASON:

Circumference(C)= 2πr

, where r is radius

Given

C= (3/2) π

So,

2\pi \: r =  \frac{3}{2}\pi

r =   \frac{\frac{3}{2}\pi}{2\pi}

r =  \frac{3}{4}

Now,

area = \pi {r}^{2}

= \pi \times  { (\frac{3}{4}) }^{2}

=  \frac{9}{16}\pi   \: {unit}^{2}

HOPE IT IS USEFUL

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At a store each notebook has a cost of x dollars. Which situation can be represented by this inequality?
kakasveta [241]

Answer:

x<1

Step-by-step explanation:

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2 years ago
Square WXYZ dilates by a factor of 1/3 with respect to the origin to create W'X'Y'Z'. If W'X' is 6 units, what is WX? *
zvonat [6]

Answer:

well you should firstcalculate the distance then divide by the primary source and you should be able to get the answer after substituting

Step-by-step explanation:

6 0
2 years ago
How much heavier is a 9 1/8 pound box than a 2 5/6 pound box?
tatuchka [14]
<span>So let’s simplify the given situation.
We need to find out how much heavier is 91/8 lbs. compare to 2 5/6 lbs.
Since, it’s a combination of whole number and fraction; we cannot directly subtract this given equation. We need to convert the two given number into a fraction.
9 1/8 = 8 x 9 = 72 + 1 = 73, 73 is our numerator and 8 is our denominator
=> 73/8
2 5/6 = 6 x 2 = 12 + 5 = 17, 17 is our numerator and 6 is our denominator
=> 17/6

Now, we have 2 fractions with unlike denominator. In order to get a common denominator, we have to find their least common factor.

=> <u>73</u> - <u>17  </u> = <u>73 x 6 </u> - <u>17 x 8 </u> <u>
</u>       8      6        8 x 6       6 x 8</span><span>
=> <u>438</u> – <u>136 </u> Now, we have the same denominator, subtract</span><span>
      48       48
=> <u>302 </u> or  <u>151</u>
       48          24
=> 6 <u>7</u>
       24
Therefore 9 1/8 lbs. is 6 7/24 lbs. heavier than 2 5/6 lbs.</span>



4 0
2 years ago
How can you estimate 1506 divided by 2so that it is close to the actual answer
likoan [24]
If you round 1506 down to 1500, then you can divide that by 2. rounding it down will make it easier.
4 0
3 years ago
Read 2 more answers
Given J(1, 1), K(3, 1), L(3, -4), and M(1, -4) and that J'(-1, 5), K'(1, 5), L'(1, 0), and M'(-1, 0). What is the rule that tran
anastassius [24]
(x; y) -> (x - 2; y + 4)

J(1; 1) ⇒ J'(1 - 2; 1 + 4) = (-1; 5)

K(3; 1) ⇒ K'(3 - 2; 1 + 4) = (1; 5)

L(3;-4) ⇒ L'(3 - 2; -4 + 4) = (1; 0)

M(1;-4) ⇒ M'(1 - 2;-4 + 4) = (-1; 0)


5 0
3 years ago
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