From one vertex of an octagon you can draw 5 diagonals.
There are 8 vertices in an octagon, and we are choosing one as our starting vertex. There are then 7 vertices left to draw a line to, but 2 of the vertices are already connected to our main vertex (because they are connected along the side of the octagon). That leaves 5 vertices to draw a diagonal to from our original vertex.
Step-by-step explanation:
If it's a straight line the use formula

m= gradient of line
c = y-intercept
we know that y-intercept is 4 so coordinate is
(0,4)
Equation also passes (2,10)
Use both coordinate to find gradient
m= vertical distance / horizontal distance
= (10-4) / (2-0)
= 3
y = 3x + 4
Answer:
<h2>x = 12</h2><h2 /><h2>y = 4√3</h2>
Step-by-step explanation:
<u>To find x we use cosine</u>
cos∅ = adjacent / hypotenuse
x is the adjacent
8√3 is the hypotenuse
cos 30 = x / 8√3
x = 8√3 cos 30
<h3>x = 12</h3>
<u>To find y we use sine</u>
sin∅ = opposite / hypotenuse
y is the opposite
8√3 is the hypotenuse
sin 30 = y / 8√3
y = 8√3 sin 30
<h3>y = 4√3</h3>
Hope this helps you
The answer would be false because the number .8 can be 8/10 but it is rational and you can understand that. It would not be an irrational number.
Answer:
The equation for the new line in slope-intercept form is:

Step-by-step explanation:
Since they give us an equation in slope-intercept form "y=4x+5", it is easy to extract the slope the new parallel line to this should have : "4" (same slope as the reference line)
We are also given a point the new line should go through : "(1, 6)"
So we can use the "point-slope" form of a line to find the equation of this new line:

which for our case is:
