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yanalaym [24]
3 years ago
13

Jerome is painting a rectangular toolbox that is 20 inches by 10 inches by 8 inches. and a tube of paint covers 300 square inche

s. What is the surface area? and how many tubes of paint should Jerome buy?
Mathematics
1 answer:
Over [174]3 years ago
6 0

Answer:

He should buy 3 tubes of paint.

Step-by-step explanation:

20×10×8=880

880÷300=2.93

2.93≈3

So, Jerome should buy 3 tubes of paint.

Brainliest please!

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miss Akunina [59]

Answer:

A. Your battery is likely defective since such poor performance is extremely unlikely.

Step-by-step explanation:

When the distribution is normal, we use the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

If X is more than two standard deviations from the mean, it is considered an unlikely outcome.

In this question, we have that:

\mu = 600, \sigma = 50

Which of the following conclusions is the most appropriate given this information?

Lasted 400 hours, so X = 400.

Z = \frac{X - \mu}{\sigma}

Z = \frac{400 - 600}{50}

Z = -4

4 standard deviations from the mean, so unlikely.

So the correct answer is:

A. Your battery is likely defective since such poor performance is extremely unlikely.

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3 years ago
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Umnica [9.8K]

Answer:

Step-by-step explanation:

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3 years ago
Square OABC is drawn on a centimetre grid. O is (0,0) A is (3,0) B is (3,3) C is (0,3) Write down how many invariant points ther
storchak [24]

Answer:

No invariant point

Step-by-step explanation:

Hello!

When we translate a form, in this case a polygon We must observe the direction of the vector. Since our vector is:

\vec{v}=\left ( \begin{matrix}1\\ 3\end{matrix} \right )

1) Let's apply  that translation to this polygon, a square. Check it below:

2) The invariant points are the points that didn't change after the transformation, simply put the points that haven't changed.

Examining the graph, we can see that no, there is not an  invariant point, after the translation. There is no common point that belongs to OABC and O'A'B'C' simultaneously. All points moved.

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Square both sides of the equation.

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