Ok! Nice question, by the way!
11 + 11 = 4
What is the sum of the digits of 11? 1 + 1 = 2.
Now square that. You get 2^2 = 4.
12 + 12 = 9
What is the sum of the digits 12? 1 + 2 = 3.
Now square that. You get 3^2 = 9.
Now, 13 + 13 = ?
What is the sum of the digit 13? 1 + 3 = 4
Now square that. You get 4^2 = 16.
13 + 13 = 16.
The coordinates of the vertex are (3, -13) and the axis of symmetry is at x = 3.
We can find the vertex by using the formula for finding x-coordinates. The formula for the x-coordinate of a vertex is below.
-b/2a
In this equation, a is the coefficient of the x^2 term (1) and b is the coefficient of the x term (-6). Then we can plug in to find the x term.
-(-6)/2(1)
6/2
3
Now that we have this term, we can plug it in for all values of x to find the y term.
x^2 - 6x - 4
3^2 - 6(3) - 4
9 - 18 - 4
-13
Now we know that the vertex is at (3, -13). Now finding the axis of symmetry is easy because the axis of symmetry in any quadratic is simply x = [x-coordinate of vertex]. So in this case it would be x = 3.
Answer:
75
Step-by-step explanation:
True.
The median is the middle number when all numbers are placed in order, and so an outlier will not affect the median.
It well however affect the range and mean
Hope this helps
Answer:
The vertex would be (1, -7/10)
Step-by-step explanation:
In order to find the vertex, start by finding the x-coordinate. The x-coordinate can be calculated using -b/2a, in which a is the coefficient of x^2 and b is the coefficient of x.
-b/2a
-(-2)/2(1)
2/2
1
Now that we know the value of the x-coordinate as 1, we can use it in the equation to find y.
y = x^2 - 2x + 3/10
y = (1)^2 - 2(1) + 3/10
y = 1 - 2 + 3/10
y = -7/10