Start with 180.
<span>Is 180 divisible by 2? Yes, so write "2" as one of the prime factors, and then work with the quotient, 90. </span>
<span>Is 90 divisible by 2? Yes, so write "2" (again) as another prime factor, then work with the quotient, 45. </span>
<span>Is 45 divisible by 2? No, so try a bigger divisor. </span>
<span>Is 45 divisible by 3? Yes, so write "3" as a prime factor, then work with the quotient, 15 </span>
<span>Is 15 divisible by 3? [Note: no need to revert to "2", because we've already divided out all the 2's] Yes, so write "3" (again) as a prime factor, then work with the quotient, 5. </span>
<span>Is 5 divisible by 3? No, so try a bigger divisor. </span>
Is 5 divisible by 4? No, so try a bigger divisor (actually, we know it can't be divisible by 4 becase it's not divisible by 2)
<span>Is 5 divisible by 5? Yes, so write "5" as a prime factor, then work with the quotient, 1 </span>
<span>Once you end up with a quotient of "1" you're done. </span>
<span>In this case, you should have written down, "2 * 2 * 3 * 3 * 5"</span>
Answer:
20 cats
Step-by-step explanation:
A proportion has to be setup to answer this
5/4 = 25/x
x represents the missing number of cats
This fraction represents the relationship amongst dogs and cats
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To solve cross multiply
5x = 100
(let me down below if you need an explanation on how to cross multiply)
Divide both sides by 5 in order to get the variable by itself
100/5 = 20
x = 20
The shelter has 20 cats
Answer:
h = -14
Step-by-step explanation:
-7πh = 98π
⇔ -7h = 98 (Just Divide both sides by π)
⇔ h = 98 ÷ (-7) = -14
Answer:
11.6 miles
Step-by-step explanation:
Given that:
Distance from J2 to J3 = 8.7 miles
Distance between J1 and J2 = 1/3 of J2 toJ3
Hence, distance between J1 and J2 becomes :
1/3 * 8.7 miles = 2.9 miles
Distance from J1 to J3 equals :
(J1 to J2) + (J2 to J3)
2.9 miles + 8.7 miles
= 11.6 miles