Answer:
The amount of water must be added to this task = 60 
Step-by-step explanation:
Let amount of water added = x
Then from the given conditions
A chemist would like to dilute a 90-cc solution that is 5% acid to one that is 3% acid. So
90 (0.05) = 0.03 ( 90 + x )
4.5 = 2.7 + 0.03 x
0.03 x = 1.8
x = 60
Therefore the amount of water must be added to this task = 60
<u>Answer:</u>
c= -1/2
<u>Step-by-step explanation:</u>
Let's solve your equation step-by-step.
4
/3 = −6c −
5/
3
Step 1: Simplify both sides of the equation.
4
/3 =−6c + −5
/3
Step 2: Flip the equation.
−6c + −5
/3 = 4/3
Step 3: Add 5/3 to both sides.
−6c + −5
/3 + 5
/3 = 4/3 + 5
/3 −6c
=3
Step 4: Divide both sides by -6.
−6c −6 = 3
− 6
c = −1
/2
Answer: 91
Step-by-step explanation:
Answer: 81
Step-by-step explanation: The median is the middle number in a sorted, ascending or descending, list of numbers and can be more descriptive of that data set than the average. Write all of the numbers and cross out a even amount of numbers on both sides. Image 1 shows your problem. If your problem had another number, you solve it differently. Check image 2.
The wall area is the product of the room perimeter and the room height:
A₁ = (2*(12.5 ft + 10.5 ft))*(8.0 ft) = 368 ft²
The window and door area together is
A₂ = 2*((4 ft)*(3 ft)) + (7 ft)*(3 ft) = 45 ft²
The area of one roll of wallpaper is
A₃ = (2.5 ft)*(30 ft) = 75 ft²
Then the number of rolls of wallpaper required will be
1.1*(A₁ - A₂)/A₃ ≈ 4.74
5 rolls of wallpaper should be purchased.
_____
As a practical matter, not much of the window and door area can be saved. The rolls are 30 inches wide, but the openings are 36 inches wide. Some will likely have to be cut from two strips. The strips will have to be the full length of the wall, and the amount cut likely cannot be used elsewhere. If the window and door area cannot be salvaged, then likely ceiling(5.4) = 6 rolls will be needed (still allowing 10% for matching and waste).
