Answer:
the answer is 19.06396
Step-by-step explanation:
there is no need for further explanation because the equation is already balanced
The answer should be positive 5 or 5
[see picture link]Area of part 1:A1=base*height/2=(8+2)*(8-2-2-1)/2=10*3/2=15 ft^2Area of part 2:A2=length*width=(8+2)*1=10 ft2Area of part 3:A3=length*width=8*2=16 ft2
Picture: https://us-static.z-dn.net/files/d30/9033549987fa60cf57fe05f71424f322.gif
Answer:
![\frac{x-16.5}{16.5}=0.30](https://tex.z-dn.net/?f=%5Cfrac%7Bx-16.5%7D%7B16.5%7D%3D0.30)
Hopefully, this is your desired setup. (I noticed the formula you have to fill in there.)
Have a good day.
Step-by-step explanation:
Hi.
You could use the percent change formula.
Since we know it is a percent increase then we will do new-old instead of old-new:
![\frac{\text{new}-\text{old}}{\old}](https://tex.z-dn.net/?f=%5Cfrac%7B%5Ctext%7Bnew%7D-%5Ctext%7Bold%7D%7D%7B%5Cold%7D)
x is the new amount of shampoo.
16.5 is the original amount (old) of shampoo.
The percent increase is 30%=0.30 .
So we have the following equation:
![\frac{x-16.5}{16.5}=0.30](https://tex.z-dn.net/?f=%5Cfrac%7Bx-16.5%7D%7B16.5%7D%3D0.30)
We could have found the equation like this:
![16.5+16.5(0.30)=x](https://tex.z-dn.net/?f=16.5%2B16.5%280.30%29%3Dx)
Subtract 16.5 on both sides:
![16.5(0.30)=x-16.5](https://tex.z-dn.net/?f=16.5%280.30%29%3Dx-16.5)
Divide both sides by 16.5:
![0.30=\frac{x-16.5}{16.5}](https://tex.z-dn.net/?f=0.30%3D%5Cfrac%7Bx-16.5%7D%7B16.5%7D)
By us of symmetric property of equality:
![\frac{x-16.5}{16.5}=0.30](https://tex.z-dn.net/?f=%5Cfrac%7Bx-16.5%7D%7B16.5%7D%3D0.30)