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2 years ago

On the day after my birthday this year, I can truthfully say: "The day after tomorrow is Monday". On which day is my birthday?

Mathematics

1 answer:

andriy [413]2 years ago

5 0

Answer: Friday

Step-by-step explanation:

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HURRY 40 POINTS !!!!!!!!! A person runs 1/4 of a mile in 1/32 of an hour. Compute the unit rate by setting up a complex fraction

hram777 [196]

I am not sure, but the best answer should be 8 miles per hour

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4 years ago

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If Acot theta + Bcot theta =4 and

geniusboy [140]

Answer is: B

Step-by-step explanation: correct answer is B

−a

Given, acotθ+bcscθ=p

bcotθ+acscθ=q

⇒p

−q

=(p−q)(p+q)

=[acotθ+bcscθ−bcotθ−acscθ][acotθ+bcscθ+bcotθ+acscθ]

=[cotθ(a−b)−cscθ(a−b)][cotθ(a+b)+cscθ(a+b)]

=(a−b)(cotθ−cscθ)(a+b)(cotθ+cscθ)

=(a

−b

)(cot

θ−csc

θ)

=(−1)(a

−b

)[∵csc

θ−cot

θ=1]

=(b

−a

)

7 0

3 years ago

I need help . i’m now in 7th grade and i don’t understand what x and y’s are .

Lady bird [3.3K]

Answer:

the x is the horizontal axis and y is the vertical axis

5 0

3 years ago

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I need help!!!!!!!!!!!

pashok25 [27]

Account 2 = 80

Account 3 = -25

Account 4 = -40

b) He's broke.

3 0

3 years ago

Find the results combining these functions.

vodomira [7]

Given $f(x) = x^2 + 6x + 9, g(x) = x^2 - 9$ :

$(f+g)(x) = (x^2 + 6x+9)+(x^2-9) =2x^2+6x=2x(x+3)$ , which is the second expression

$(f-g)(x) = (x^2 + 6x+9)-(x^2-9) =6x+18=6(x+3)$ , which is the first second expression

$(fxg)(x) = (x^2+6x+9)(x^2-9) = (x^4-9x^2)+(6x^3-54x)+(9x^2-81)=x^4+6x^3-54x-81$ , which is the fourth expression

$(f/g)(x) = (x^2+6x+9)/(x^2-9) = \frac{(x+3)^2}{(x+3)(x-3)} = \frac{x+3}{x-3}$ , which is the third expression

4 0

3 years ago