Answer:
The measure of the third arc is ![150\°](https://tex.z-dn.net/?f=150%5C%C2%B0)
Step-by-step explanation:
step 1
we know that
The measurement of the external angle is the semi-difference of the arcs which comprises
in this problem
Let
x----> the greater arc of the circle intercepted by the secant and the tangent
y----> the smaller arc of the circle intercepted by the secant and the tangent
![42\°=\frac{1}{2}(x-y)](https://tex.z-dn.net/?f=42%5C%C2%B0%3D%5Cfrac%7B1%7D%7B2%7D%28x-y%29)
----> equation A
![\frac{x}{y}=\frac{7}{3}](https://tex.z-dn.net/?f=%5Cfrac%7Bx%7D%7By%7D%3D%5Cfrac%7B7%7D%7B3%7D)
-----> equation B
Substitute equation B in equation A and solve for y
![y=3*84\°/4=63\°](https://tex.z-dn.net/?f=y%3D3%2A84%5C%C2%B0%2F4%3D63%5C%C2%B0)
Find the value of x
![x=\frac{7}{3}(63\°)=147\°](https://tex.z-dn.net/?f=x%3D%5Cfrac%7B7%7D%7B3%7D%2863%5C%C2%B0%29%3D147%5C%C2%B0)
step 2
Find the measure of the third arc
Let
z------> the measure of the third arc
we know that
-----> complete circle
substitute the values and solve for z
![147\°+63\°+z=360\°](https://tex.z-dn.net/?f=147%5C%C2%B0%2B63%5C%C2%B0%2Bz%3D360%5C%C2%B0)
![z=360\°-(147\°+63\°)=150\°](https://tex.z-dn.net/?f=z%3D360%5C%C2%B0-%28147%5C%C2%B0%2B63%5C%C2%B0%29%3D150%5C%C2%B0)
C 1/2 is the correct answer
Answer:
1. y² - 3x - 18
2. 4x² - 33x + 35
3. 12x² - 11x + 2
Step-by-step explanation:
All we do with these questions are expanding the factored binomials. Use FOIL:
1. y² + 3y - 6y - 18
y² - 3y - 18
2. 4x² - 28x - 5x + 35
4x² - 33x + 35
3. 12x² - 3x - 8x + 2
12x² - 11x + 2
Answer:
32.4
Step-by-step explanation:
prior + 8.1 = 40.5 . . . . . . seems to model the problem statement
prior = 32.4 . . . . . . . subtract 8.1 from both sides
Prior to the increase the percent was 32.4.
_____
<em>Comment on the problem statement</em>
When you're talking about a percentage increase in a percentage, it is almost never clear whether you're talking about the percentage of the underlying number, or the percentage of the percentage.
Here, we assume the 8.1 is a percentage of working students, not a percentage of the percentage of workings students. If you actually intend the latter, the percentage before the increase was about 37.465%.