This is the concept of polynomials, to get the relationship between the (x-3) and (x^3+4x^2+2) we shall proceed as follows;
we first test if (x-3) is a polynomial;
x-3=0
thus;
x=3
substituting the value of x in the polynomial we get:
(3)^3+4(3)^2+2
=65
since the result is not equal to 0, we conclude that there is no relationship between (x-3) and the polynomial. The answer is B. (X-3) is not a factor
Answer:
The student ticket is 200 and the adults is 550
Step-by-step explanation:
So the set up is :
750 = x + y
5300 = 8x + 4.5 y
x will be adults and y will be students
Assuming you don't have calculator then you want to be able to eliminate either x or y from this system. The easiest is X cause its a whole number.
So multiply all the numbers from the first equation by 8 which gives
6000 = 8x + 8 y
5300 = 8x + 4.5 y
Then subtract the numbers (6000-5300 and 8x-8x and 8y-4.5y)
which gives :
700 = 3.5y
Solve for y = 200
and plug 200 back into any equation to solve for X
750 = x + 200
x = 550
,make y the subject
2y=b-4x
divide all sides by 2
y=b\2-4x\2
