Answer:
Step-by-step explanation:
Like terms: 10y, -2y, 3x, and x
These are all like terms since they have a similar variable
Simplifying the expressions:
10y + 3x + 10 + x -2y = [(10y + -2y) + (3x + x)] + 10
= 8y + 4x + 10
Like terms: 3x, 4x, y, and -2y
Same as first explanation, terms have a similar variable
3x - y + 4x + 6 - 2y = (3x + 4x) + (-2y - y) + 6
= -3y + 7x + 6
Hope I helped :)
Answer:
y=3x+1, or the second option
Step-by-step explanation:
We can see on the graph the line converges with the y-axis at (0, 1), so we can cross out the last two answers. Then we can also see that the slope is 3 on the graph and an equation that has x^2 must be a parabola. The answer is then narrowed down to the second option.
<span>Let n be the number of taxis in NY. The average distance travelled is 60,000 miles, therefore the middle 95% will have the same average as the population, the reason being the mileage is symmetrically distributed about the mean Therefore the total number of miles in one year for the middle 95% is 60,000 * 0.95 * n
</span><span>The range of miles driven by the middle 95% can be found from the empirical rule that says:
For a normal distribution, approximately 95% of the data points lie within the range plus and minus 2 standard deviations of the population mean. In this case the range is
(60,000-22,000) to (60,000 + 22,000)</span>
Answer:
Her average speed is 94 km/h
Time taken is 3.5 hours
Step-by-step explanation:
Let Evan’s average speed be x km/h.
now since Meghan drove faster, according to the question, we can say her average speed would be x + 6 km/h
Mathematically, time = distance/speed
so; since time is the same; we have
308/x = 329/(x + 6)
cross multiply
329(x) = 308(x + 6)
329x = 308x + 1848
329x-308x = 1848
21x = 1848
x = 1848/21
x = 88 km/h
Meghan average speed = x + 6 = 88 + 6 = 94 km/h
Time taken would be 329/94 = 3.5 hours
This is a parabola that opens downward.
Remember that the axis of symmetry is located at x=-b/(2a).
So the vertex is at (3,-1)
So functions slope is positive or increasing on (-co, 3] and decreasing on [3,co).
