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makkiz [27]
3 years ago
8

What is a correct congruence statement for the triangles shown? Enter your answer in the box. ​ △ ​ ​ ≅△PFX

Mathematics
2 answers:
andrew11 [14]3 years ago
6 0

Answer:

ΔBLG ≅ ΔPFX

Step-by-step explanation:

Here it is given that ∠B≅<P.

Also its given that

BL ≅PF

The angle opposite BL is ∠G

The angle opposite PF is ∠X

∠G ≅ ∠X

Again

BG ≅PX

The angle opposite BG is ∠L

The angle opposite PX is ∠F

So ∠L ≅ ∠F

Hence B in place of P

L in place of F

G in place of X

So for ΔPFX, the corresponding triangle is ΔBLG

Hence

ΔBLG ≅ ΔPFX


alina1380 [7]3 years ago
5 0

Answer:

ΔBLG ≅ ΔPFX

Step-by-step explanation:

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Step-by-step explanation:

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3 years ago
An angle measures 38° more than the measure of its complementary angle. What is the measure of each angle?
seropon [69]
Answer: 38° and 52°

Steps:
x + 38° = 90°
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6 0
3 years ago
How much does a sleeping bag cost? Let's say you want a sleeping bag that should keep you warm in temperatures from 20°F to 45°F
BARSIC [14]

Answer:

a) Sample Mean = 79.4

Sample standard deviation = 30.62

b) 90% Confidence interval:  (67.56 ,91.24)

Step-by-step explanation:

We are given the following in the question:

Prices for sleeping bags has an approximately normal distribution.

We are given the following sample:

35, 85, 105, 40, 100, 50, 30, 23, 100, 110, 105, 95, 105, 60, 110, 120, 95, 90, 60, 70

a)

Formula:

\text{Standard Deviation} = \sqrt{\displaystyle\frac{\sum (x_i -\bar{x})^2}{n-1}}  

where x_i are data points, \bar{x} is the mean and n is the number of observations.  

Mean = \displaystyle\frac{\text{Sum of all observations}}{\text{Total number of observation}}

Mean =\displaystyle\frac{1588}{20} = 79.4

Sum of squares of differences = 1971.36 + 31.36 + 655.36 + 1552.36 + 424.36 + 864.36 + 2440.36 + 3180.96 + 424.36 + 936.36 + 655.36 + 243.36 + 655.36 + 376.36 + 936.36 + 1648.36 + 243.36 + 112.36 + 376.36 + 88.36 = 17816.8

S.D = \sqrt{\displaystyle\frac{17816.8}{19}} = 30.62

b) 90% Confidence interval:  

\bar{x} \pm t_{critical}\displaystyle\frac{s}{\sqrt{n}}  

Putting the values, we get,  

t_{critical}\text{ at degree of freedom 19 and}~\alpha_{0.10} = \pm 1.7291  

79.4 \pm 1.73(\displaystyle\frac{ 30.62}{\sqrt{20}} ) = 79.4 \pm 11.84 = (67.56 ,91.24)

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