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makkiz [27]
3 years ago
8

What is a correct congruence statement for the triangles shown? Enter your answer in the box. ​ △ ​ ​ ≅△PFX

Mathematics
2 answers:
andrew11 [14]3 years ago
6 0

Answer:

ΔBLG ≅ ΔPFX

Step-by-step explanation:

Here it is given that ∠B≅<P.

Also its given that

BL ≅PF

The angle opposite BL is ∠G

The angle opposite PF is ∠X

∠G ≅ ∠X

Again

BG ≅PX

The angle opposite BG is ∠L

The angle opposite PX is ∠F

So ∠L ≅ ∠F

Hence B in place of P

L in place of F

G in place of X

So for ΔPFX, the corresponding triangle is ΔBLG

Hence

ΔBLG ≅ ΔPFX


alina1380 [7]3 years ago
5 0

Answer:

ΔBLG ≅ ΔPFX

Step-by-step explanation:

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3 0
3 years ago
If Log 4 (x) = 12, then log 2 (x / 4) is equal to <br>A. 11 <br>B. 48 <br>C. -12 <br>D. 22
klio [65]
C I guess sorry if I get you a low score
6 0
4 years ago
ANSWER IF YOU LOVE YOUR LORD!!!! Which graph represents the solution to: 2k+8&lt;5k-1?
Leviafan [203]

Answer:

Third graph

Step-by-step explanation:

First, find the solution to the equation of inequality given.

2k + 8 < 5k - 1

Subtract 5k from both sides

2k + 8 - 5k < 5k - 1 - 5k

-3k + 8 < -1

Subtract 8 from both sides

-3k + 8 - 8 < -1 - 8

-3k < -9

Divide both sides by -3. (Note: < will change to > when dividing both sides with negative number)

\frac{-3k}{-3} > \frac{-9}{-3}

k > 3

The graph that will represent this solution will show that all values of k are greater than 3. 3 is not included as a solution. The "o" on top of the 3 on the number line won't be shaded to indicate that 3 is not included. And also, the arrow will point from 3 towards our right.

Therefore, the 3rd graph is the answer.

3 0
3 years ago
Which value of x makes the equation 2/3x-3=11 true?
harkovskaia [24]

Answer:

x = 21

Step-by-step explanation:

To see for what value of x is the equation true, we have to solve x.

\displaystyle \frac{2}{3} x - 3 = 11\\\\Adding \ 3 \ to \ both \ sides\\\\\frac{2x}{3} = 11 + 3\\\\\frac{2x}{3} = 14\\\\Multiply \ 3 \ to \ both \ sides\\\\2x = 14 \times 3\\\\2x = 42 \\\\Divide\ both\ sides\ by\ 2\\\\x = 42/2\\\\x = 21\\\\For \ x = 21\ the \ given \ equation \ is \ true.\\\\\rule[225]{225}{2}

Hope this helped!

<h3>~AH1807</h3><h3>Peace!</h3>
7 0
3 years ago
I'm solving systems and I don't understand how to do it pls helpp
kaheart [24]

Answer:

Use the process of elimination. I'll only do one example since you have 4.

Step-by-step explanation:

Let's do the first question.

2x-3y=-11

2x+y=9

Our goal here is to be left with one variable to solve, this way we can use the answer for that variable to find the other. A.K.A only find X to plug into the equation to find Y. To do this, we'll use the process of elimination, in which we need to cancel out a variable.

X seems the easiest here. To cancel 2 (in the top equation), you need to have a -2. And that -2 needs to be the x coefficient in the 2nd equation, in order for us to "cancel" it out. To get -2, you multiply 2 by -1.

-1(2x+y)= -1(9)

Note that whatever you do to one side, you need to do it to both sides! Hence, why I also multiplied 9 by -1. You should now be left with:

-2x -y = -9

Now, we cancel out the positive 2 and -2 from both equations by adding the two equations.

2x-3y= 11

+

-2x-y=-9

X cancels out, so we're left with -4y=-20. Solve for Y, which is 5.

-4y=-20

y=5

Now that you have the Y value, plug it into any of the two equations to find your X value.

2x-3y=11

2x-3(5)=11

2x-15=11

2x=26

x=13

And voilah! Our Y value is 5, and our X value is 13.

It's pretty simple once you understand what's going on. All that we did was to cancel out one variable (either X or Y) in the two equations so that we're left with only one variable to solve. If we cancel out X, we only need to solve for Y. You do this by manipulating one of the two equations (doesn't matter which one). Once you find either X or Y, all you need to is to plug it into one of the original equations. Then, you'll have both X and Y.

And that my friend, is the process of elimination. Good luck!

8 0
3 years ago
Read 2 more answers
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