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andreev551 [17]
3 years ago
5

Write the point-slope form of the line that passes through (5, 5) and is PARALLEL to a line with a slope of 1/4. Include all of

your work in your final answer.
Write the point-slope form of the line that passes through (5, 5) and is PERPENDICULAR to a line with a slope of 1/4.

PLEASE HELP!
Mathematics
1 answer:
lesya692 [45]3 years ago
4 0
Parallel lines will have the same slope

y - y1 = m(x - 1)
slope(m) = 1/4
(5,5)...x1 = 5 and y1 = 5
now we sub
y - 5 = 1/4(x - 5) <==== ur parallel line
==================
perpendiculr lines will have a negative reciprocal slope. To find the negative reciprocal, u flip the number and change the sign. So the negative reciprocal of 1/4 is -4....see how I flipped 1/4 and made it 4/1...then changed the sign making it -4/1 or just -4. That will be ur slope of the perpendicular line.

y - y1 = m(x - x1)
slope(m) = -4
(5,5)...x1 = 5 and y1 = 5
now we sub
y - 5 = -4(x - 5) <=== ur perpendicular line
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The coordinate of the vertex is; (h, k) = (3, -5)

The final equation of the parabola is; y = 5(x - 3)² - 5

<h3>How to find the vertex of a Parabola?</h3>

The vertex is the coordinate of the crest or trough of the curve. Now, in the given graph, we only have a Trough which is the lowest point of the graph.

The coordinate of the vertex is; (h, k) = (3, -5)

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