All categories

2 years ago

Define bartering. Exchanging goods or services directly, without a medium of exchange.

Mathematics

1 answer:

Katyanochek1 [597]2 years ago

7 0

Answer:

Bartering is the act of trading one good or service for another without using a medium of exchange such as money

You might be interested in

A rectangle has one side that measures 3x + 1 and another that measures 4y + 3. Keith says that the perimeter of the rectangle i

mart [117]

Answer:

he added the dimensions of the rectangle. He used the wrong formula. the formula he used was length + breadth. He should have multiplied by 2

6x + 8y +8

Step-by-step explanation:

Perimeter of a rectangle = 2 x (L + B)

L = length

b = breadth

2 (3x + 4y + 4. ) = 6x + 8y +8

5 0

3 years ago

What are some ways you can make a rectangle 10,000 cm squared (I NEED A AWNSER QUICK)

lidiya [134]

Answer:

2 longer sides would be 4000 each, so that's 8000 total

and the 2 shorter sides could be 1000 each, so that's 2000 total

8000+2000=10,000

Step-by-step explanation:

8 0

3 years ago

Heather won 100 lollipops playing horseshoes at her school's game night. Later, she gave four to each of her friends. She only h

vova2212 [387]

Answer:

23 friends

Step-by-step explanation:

100 - 8= 92

92/4 = 23

HEATHER IS SO POPULAR!!

8 0

3 years ago

Which graph shows the solution to the system of equations 2x + y = 4 and 3x - 2y = 6?

defon

Answer: 2,0

hope this helps :)

4 0

3 years ago

A quality analyst of a tennis racquet manufacturing plant investigates if the length of a junior's tennis racquet conforms to th

Burka [1]

Answer:

Confidence interval : $21.506$ to $24.493$

Step-by-step explanation:

A quality analyst selects twenty racquets and obtains the following lengths:

21, 25, 23, 22, 24, 21, 25, 21, 23, 26, 21, 24, 22, 24, 23, 21, 21, 26, 23, 24

So, sample size = n =20

Now we are supposed to find Construct a 99.9% confidence interval for the mean length of all the junior's tennis racquets manufactured at this plant.

Since n < 30

So we will use t-distribution

Confidence level = 99.9%

Significance level = α = 0.001

Now calculate the sample mean

X=21, 25, 23, 22, 24, 21, 25, 21, 23, 26, 21, 24, 22, 24, 23, 21, 21, 26, 23, 24

Sample mean = $\bar{x}=\frac{\sum x}{n}$

Sample mean = $\bar{x}=\frac{21+25+23+22+24+21+25+21+23+ 26+ 21+24+22+ 24+23+21+ 21+ 26+23+ 24}{20}$

Sample mean = $\bar{x}=23$

Sample standard deviation = $\sqrt{\frac{\sum(x-\bar{x})^2}{n-1}}$

Sample standard deviation = $\sqrt{\frac{(21-23)^2+(25-23)^2+(23-23)^2+(22-23)^2+(24-23)^2+(21-23)^2+(25-23)^2+(21-23)^2+(23-23)^2+(26-23)^2+(21-23)^2+(24-23)^2+(22-23)^2+(24-23)^2+(23-23)^2+(21-23)^2+(21-23)^2+(26-23)^2+(23-23)^2+(24-23)^2}{20-1}}$

Sample standard deviation= s = $1.72$

Degree of freedom = n-1 = 20-1 -19

Critical value of t using the t-distribution table $t_{\frac{\alpha}{2}$ = 3.883

Formula of confidence interval : $\bar{x} \pm t_{\frac{\alpha}{2}} \times \frac{s}{\sqrt{n}}$

Substitute the values in the formula

Confidence interval : $23 \pm 1.73 \times \frac{1.72}{\sqrt{20}}$

Confidence interval : $23 -3.883 \times \frac{1.72}{\sqrt{20}}$ to $23 + 3.883 \times \frac{1.72}{\sqrt{20}}$

Confidence interval : $21.506$ to $24.493$

Hence Confidence interval : $21.506$ to $24.493$

3 0

3 years ago

Read 2 more answers