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2 years ago

The difference between the two numbers is 48. The ratio of the two numbers is 7:3. What are the two numbers?

Mathematics

2 answers:

OlgaM077 [116]2 years ago

6 0

Let the bigger no. be X and the smaller no. be Y

X-Y=48

7-3=4

48÷4=12

X=12×7=84

Y=12×3=36

kvv77 [185]2 years ago

6 0

Answer:

https://www.youtu

be.com/watch?v=

L6DytTom53A

Step-by-step explanation:

X-Y=48

7-3=4

48÷4=12

X=12×7=84

Y=12×3=36

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HELP!!!!!! I believe its B but I am not sure! :(

n200080 [17]

Answer:

Step-by-step explanation:

When solving for x as an exponent, we need to use logarithms in order to undo the operation and rearrange the terms. We use log rules to bring down the exponent and solve. Logarithms are the inverse operations to exponents and vice versa. We have one special kind of logarithm called the natural logarithm whose base is e. We write it as ln. Since our base is e here, we will use the natural logarithm to rearrange and isolate x.

$e^{4x-1} =3$

We begin by applying the natural logarithm to each side.

$ln(e^{4x-1}) =ln(3)$

Log rules allow use to rearrange the exponent as multiplication in front of the log.

$(4x-1)ln(e) =ln(3)$

ln e as an inverse simplifies to 1.

$(4x-1)(1)=ln(3)$

We now apply the inverse operations for subtraction and multiplication.

$4x-1+1=1+ln(3)\\4x=1+ln(3)\\\frac{4x}{4} =\frac{1+ln3}{4} \\x =\frac{1+ln3}{4}$

Option A is correct.

5 0

3 years ago

Each locker is shaped like a rectangular prism. Which has more storage space? explain/

seropon [69]

Locker 1 has more storage space because it has a greater volume.
The volume of locker 1 is 8,640 (48x15x12)
The volume of locker 2 is 7,200 (60x10x12)

I hope this helps.

4 0

3 years ago

9 Acolle mayurae Kopo ro

Lelechka [254]

Answer:

huh

Step-by-step explanation:

5 0

2 years ago

A student is given that point P(a, b) lies on the terminal ray of angle Theta, which is between StartFraction 3 pi Over 2 EndFra

Harman [31]

Answer:

A.

The student made an error in step 3 because a is positive in Quadrant IV; therefore,

$cos\theta = \frac{a\sqrt{a^2 + b^2}}{a^2 + b^2}$

Step-by-step explanation:

Given

$P\ (a,b)$

$r = \± \sqrt{(a)^2 + (b)^2}$

$cos\theta = \frac{-a}{\sqrt{a^2 + b^2}} = -\frac{\sqrt{a^2 + b^2}}{a^2 + b^2}$

Required

Where and which error did the student make

Given that the angle is in the 4th quadrant;

The value of r is positive, a is positive but b is negative;

Hence;

$r = \sqrt{(a)^2 + (b)^2}$

Since a belongs to the x axis and b belongs to the y axis;

$cos\theta$ is calculated as thus

$cos\theta = \frac{a}{r}$

Substitute $r = \sqrt{(a)^2 + (b)^2}$

$cos\theta = \frac{a}{\sqrt{(a)^2 + (b)^2}}$

$cos\theta = \frac{a}{\sqrt{a^2 + b^2}}$

Rationalize the denominator

$cos\theta = \frac{a}{\sqrt{a^2 + b^2}} * \frac{\sqrt{a^2 + b^2}}{\sqrt{a^2 + b^2}}$

$cos\theta = \frac{a\sqrt{a^2 + b^2}}{a^2 + b^2}$

So, from the list of given options;

The student's mistake is that a is positive in quadrant iv and his error is in step 3

3 0

2 years ago

the measure of the angle is 88 degrees greater than its complement. what is the measure of the complement?

vazorg [7]

Let the angle be x and it's complement be c.

Then, x = c + 88 and x + c = 90

Substitute the first equation in the second.

(c+88) + c = 90
2c+88 = 90
2c = 2
c =1

Compliment = 1
Angle = 89

6 0

3 years ago