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garik1379 [7]
3 years ago
12

The substance x and y had retention times of 16.4 and 17.63 minutes on a 30 cm column. unretained species had 1.30 minutes reten

tion time. the peak widths (wi) were 1.11 and 1.21 min, respectively. calculate column resolution, average number of plates, and plate height.
Mathematics
1 answer:
s2008m [1.1K]3 years ago
3 0
Column Resolution
Rs = 2[(tr)y - (tr)x]/[Wx + Wy]
= 2[17.63 - 16.4]/ [1.11 + 1.21] = 1.06

Average no. of plates in the column for substance x 
N = 16(tr/ W)^2
N = 16(16.4/1.11)^2
N = 3490 plates 

Average no. of plates in the column for substance y 
N = 16(tr/ W)^2
N = 16(17.63/1.21)^2
N = 3397 plates 

Plates Height
H = L/N

For substance x 
H = 30/3490
H= 0.00916905 cm/plate 

For substance y 
H = 30/3397
H = 0.00883132 cm/plate 





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Step-by-step explanation:

1. Calculate Σx, Σy, Σxy, and Σx²  

The calculation is tedious but not difficult.

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2. Calculate the coefficients in the regression equation

a = \dfrac{\sum y \sum x^{2} - \sum x \sum xy}{n\sum x^{2}- \left (\sum x\right )^{2}} =  \dfrac{503.7 \times 3425447 - 5609 \times 308049.76}{10 \times 3425447- 5609^{2}}\\\\= \dfrac{1725466163 - 1727851103.84}{34254470 - 31460881} = -\dfrac{2384941}{2793589}= \mathbf{-0.8537}

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To two decimal places, the regression equation is

y = -0.85 + 0.09x

3. Prediction

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y = -0.85 + 0.09x = -0.85 + 0.09 × 563 = -0.85  + 50.67 = $49.82

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