P = 3
n = 5
N = 15
<span><span><span>x </span><span>¯ </span></span> </span>
= 16
<span><span>SST</span> </span>
= <span><span>∑n(x−<span><span>x </span><span>¯ </span></span><span><span>) </span><span>2 </span></span></span> </span>
<span><span>SST</span> </span>
= <span><span>5(12−16<span><span>) </span><span>2 </span></span>+5(16−16<span><span>) </span><span>2 </span></span>+11(20−16<span><span>) </span><span>2 </span></span></span> </span>
= 160
<span><span>MST</span> </span>
= <span><span><span><span>SST</span><span>p−1</span> </span> </span>
</span>
<span><span>MST</span> </span>
= <span><span><span>160<span>3−1</span> </span> </span>
</span>
= 80
<span><span>SSE</span> </span>
= <span><span>∑(n−1)<span><span>S </span><span>2 </span></span></span> </span>
SSE = 4*4 + 4*1 + 4*16
= 84
<span><span>MSE</span> </span>
= <span><span><span><span>SSE</span><span>N−p</span> </span> </span>
</span>
<span><span>MSE</span> </span>
= <span><span><span>84<span>15−3</span> </span> </span>
</span>
MSE = 7
<span>F </span>
= <span><span><span><span>MST</span><span>MSE</span> </span> </span>
</span>
<span>F </span>
= <span><span><span>807 </span> </span>
</span>
= 11.429
It is important to understand the meaning of orthocenter in respect to a triangle first. Ii is actually the intersection of all the altitudes within a triangle. The altitudes can be drawn from an angle to the opposite side but the line should create a right angle with the side of the triangle. In case of obtuse triangle, the three lines would meet outside the triangle. I hope the answer helps.
I'm guessing your problem is this:
y³ - 9y² + y - 9 = 0
right?
In solving this problem, I recommend doing this:
y³ - 9y² + y - 9 = 0
Factor out a y² from the first two numbers in the problem:
y²(y - 9) + (y - 9) = 0
Separate the parentheses which means y - 9 goes on one side. The y² added a one since it came from the + 1 in the middle of expression. When you're separating parentheses like this you just take the outside numbers and combine them together. Since + 1 came from the outside of the (y - 9) and y² also was sitting on the outside of (y - 9) combine them to make y² + 1. Like this:
(y² + 1)(y - 9) = 0
Now separate your two parentheses to two separate problems:
(y² + 1) = 0 and (y - 9) = 0
Now you're y² + 1 will equal:
y² = -1
y = √-1 <-- This number doesn't exist so it will be an imaginary number (i). If you guys didn't learn that in your class I recommend just leaving it as i for that part.
Now solve y - 9 = 0:
y = 9 <-- Since we added nine to both sides to get this.
So you're final answer should be y = i and 9
If the perimeter is 39 what you have to do is 39 - 8.5 - 8.5 that will give you 22 and divide 22/2 and that gives you 11. So 11 is the length