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Tcecarenko [31]
3 years ago
9

Tobin rows 2 miles per hour faster than her opponent. If it takes Tobin 30 minutes to finish a race, and it takes her opponent 4

5 minutes to finish the same race, how fast does Tobin row? PS: I know this question was asked before, but the answers didn't have explanations I fully understood. Thanks
Mathematics
1 answer:
Sunny_sXe [5.5K]3 years ago
6 0
If we represent Tobin's speed as x, we can write her opponent's speed as 
x-2 (since Tobin is 2 more than them). In addition, since it's in miles per hour, and 45 minutes is 3/4 of an hour, we can say that 3/4ths of her speed in miles per hour is how long the race is, so (3/4)(x-2)=distance of race. In addition, since it only took Tobin 30 minutes, and 30 minutes is half an hour, x/2 (half of her miles per hour) is the length of the race, so (3/4)(x-2)=(1/2)x. Expanding it, we get 3x/4-6/4=x/2. Subtracting x/2 (or 2x/4) from both sides, we get x/4-6/4=0 and by adding 6/4 to both sides we get x/4=6/4. Multiplying 4 to both sides, we get that x=6=Tobin's speed in miles per hour
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Step-by-step explanation:

Let

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we have

z=4

<em>Find the value of x</em>

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<em>Find the value of y</em>

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y=\frac{3}{4}(4)

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almond=3

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vanilla=?

almond=6

pineapple=?

we have

y=6

<em>Find the value of x</em>

substitute the value of y in equation A

x=\frac{6}{3}=2

<em>Find the value of z</em>

substitute the value of x in equation B

2=\frac{1}{4}z

solve for z

z=8

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vanilla=2

almond=6

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we have

x=1\frac{1}{2}

convert to an improper fraction

x=1\frac{1}{2}=\frac{1*2+1}{2}=\frac{3}{2}

<em>Find the value of y</em>

substitute the value of x in equation A

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substitute the value of x in equation B

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therefore

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