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Tcecarenko [31]
3 years ago
9

Tobin rows 2 miles per hour faster than her opponent. If it takes Tobin 30 minutes to finish a race, and it takes her opponent 4

5 minutes to finish the same race, how fast does Tobin row? PS: I know this question was asked before, but the answers didn't have explanations I fully understood. Thanks
Mathematics
1 answer:
Sunny_sXe [5.5K]3 years ago
6 0
If we represent Tobin's speed as x, we can write her opponent's speed as 
x-2 (since Tobin is 2 more than them). In addition, since it's in miles per hour, and 45 minutes is 3/4 of an hour, we can say that 3/4ths of her speed in miles per hour is how long the race is, so (3/4)(x-2)=distance of race. In addition, since it only took Tobin 30 minutes, and 30 minutes is half an hour, x/2 (half of her miles per hour) is the length of the race, so (3/4)(x-2)=(1/2)x. Expanding it, we get 3x/4-6/4=x/2. Subtracting x/2 (or 2x/4) from both sides, we get x/4-6/4=0 and by adding 6/4 to both sides we get x/4=6/4. Multiplying 4 to both sides, we get that x=6=Tobin's speed in miles per hour
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Enter the next three numbers of the repeating decimal produced by the
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3 years ago
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The answer to the question

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3 years ago
Read 2 more answers
WILL MARK BRAINLIEST IF CORRECT PLEASE HELP
Romashka [77]

Answer:

\frac{4\sqrt{7}}{7} \text{ and } \frac{3\sqrt{7}}{7}

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if \sec x = \frac{4}{3}, then that means that it is the angle of a right triangle with the hypotenuse equal to 4 and one of the legs (specifically the adjacent leg) equal to 3, since sec(x) is defined as hypotenuse over the adjacent side.

The other leg (specifically the opposite one) will be equal to \sqrt{16-9} = \sqrt{7} by the pythagorean theorem, so csc(x) = hypotenuse over opposite side = \frac{4}{\sqrt{7}}=\frac{4\sqrt{7}}{7}.

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