Answer:
B. $715
Step-by-step explanation:
By multiplying your starting value, in this case $550, and your (simple) interest, 6%, or by 1.06 as 0.06 being your interest value and the 1.00 accommodating your starting value you will multiply, $550 × 1.06 = $583. Repeat these steps for however many years you are account for, in this case, five years. Giving you a total of $715
The equation of the tangent line at x=1 can be written in point-slope form as
... L(x) = f'(1)(x -1) +f(1)
The derivative is ...
... f'(x) = 4x^3 +4x
so the slope of the tangent line is f'(1) = 4+4 = 8.
The value of the function at x=1 is
... f(1) = 1^4 +2·1^2 = 3
So, your linearization is ...
... L(x) = 8(x -1) +3
or
... L(x) = 8x -5
If you multiply 8.5 by 50 cents your answer will be 4.25