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3 years ago

6

Help me (once again!)

1 answer:

Andrew [12]3 years ago

4 0

//I will only be using < instead of less than or equal to for this, as its quicker.
Move all over to LHS to have only one side of an inequality with "x".
3x^2 - 4x - ((6x^2 - 3x + 5)/10) < 0.
30x^2 - 40x - 6x^2 + 3x - 5 < 0
24x^2 - 37x -5< 0

So x is between -0.125 and 1.666...
The only integer solutions are 0 and 1, therefore there are 2 solutions.

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What is the equation of line perpendicular to y-3=-4(x+2) and passee through the point (-5,7

netineya [11]

Answer: $y=\frac{1}{4}x+\frac{33}{4}$

Step-by-step explanation:

1. By definition, two slopes are perpendicular if their slopes are negative reciprocals of each other. So, let's find the slope of the other line.

2. The equation given in the problem is written in Point-slope form:

$y-y_1=m(x-x_1)$

Where m is the slope.

3. Therefore, the slope of its perpendicular line must be:

$m=\frac{1}{4}$

4. You have the point (-5,7), so you can substitute it into the point-slope formula to find the equation of the new line:

$y-7=\frac{1}{4}(x+5)$

5. In slope intercept form is:

$y=\frac{1}{4}x+\frac{5}{4}+7\\y=\frac{1}{4}x+\frac{33}{4}$

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3 years ago

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Sergeeva-Olga [200]

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Step-by-step explanation:

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3 years ago

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3 years ago

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2 years ago

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Pepsi [2]

-2y-4=4y-4
2) cancel 4 out on both sides
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4 years ago

Read 2 more answers