Answer:
z(max) = 256000 Php
x₁ = 10
x₂ = 110
Step-by-step explanation:
Jogging pants design Selling Price Cost
weekly production
Design A x₁ 2500 1750
Design B x₂ 2100 1200
1. z ( function is : )
z = 2500*x₁ + 2100*x₂ to maximize
First constraint weekly production
x₁ + x₂ ≤ 120
Second constraint Budget
1750*x₁ + 1200*x₂ ≤ 150000
Then the model is
z = 2500*x₁ + 2100*x₂ to maximize
Subject to
x₁ + x₂ ≤ 120
1750*x₁ + 1200*x₂ ≤ 150000
General constraints x₁ ≥ 0 x₂ ≥ 0 both integers
First table
z x₁ x₂ s₁ s₂ cte
1 -2500 -2100 0 0 0
0 1 1 1 0 = 120
0 1750 1200 0 1 = 150000
Using AtoZmath online solver and after 6 iterations the solution is:
z(max) = 256000 Php
x₁ = 10
x₂ = 110
I think Larry is 1/10 closer to Brianna's than Katie.
Answer:
325 and 375 mph
Step-by-step explanation:
Given :
Distance between plane A and B = 2800
Recall :
Distance = speed * time
Let speed of A = v1
Speed of B = v2
v1 = v2 + 50
Time taken = 4 hours
Distance = speed * time
Total distance = 2800
2800 = v1 * 4 + v2 * 4
2800 = (4v1) + (4v2)
2800 = 4(v2+50) + 4v2
2800 = 4v2 + 200 + 4v2
2800 = 8v2 + 200
2800 - 200 = 8v2
2600 = 8v2
v2 = 2600/8
v2 = 325 mph
v1 = v2 + 50
v1 = 325 + 50
v1 = 375 mph
Answer:
-10
Step-by-step explanation:
-4 + -3 = -7
-7 + -2 = -9
-9 + -1 = -10
